CODEWITHSUNDEEP
c#generics
crichavin
crichavin

Reputation: 4582

Is there a way to pass additional arguments to a Converter in List.ConvertAll

Referencing CovertAll.

It doesn't seem like there is a way, but I have a value that needs to be updated in each element of the list that is not part of the source list. I have many other places in this project using .ConvertAll but in this one place I need to pass in an additional parameter and was hoping to keep it consistent using .ConvertAll.

.i.e looking for something like this: lstNewStoreFrontOrders.ConvertAll(Order.ConvertToOrderDto(storeFront.Id))

public static OrderHeaderImportDTO ConvertToOrderDto(Order storeFrontOrder, int storeFrontId)
{
    var orderHeader = new OrderHeaderImportDTO() {
        StatusId = ORDER_CREATED,
        StoreFrontId = storeFrontId,
        .....
}

Upvotes: 1

Views: 343

Answers (1)

canton7
canton7

Reputation: 42320

Sure, just use a lambda expression which captures storeFront.Id:

lstNewStoreFrontOrders.ConvertAll(order => Order.ConvertToOrderDto(order, storeFront.Id))

After all, orders.ConvertAll(Foo) is more or less just shorthand for orders.ConvertAll(order => Foo(order)).

Upvotes: 5

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