Reputation: 543
For example, I have two tables:
ID | Name
------------
1 | test 1
2 | test 2
ID2| ID | Age
--------------
1 | 1 | 18
2 | 1 | 18
3 | 1 | 19
4 | 2 | 18
5 | 2 | 19
I want to have all records that have columns which are multiple in name with age but I don't know how to do that.
I want an output like this:
Name | Age
--------------------
test 1 | 18
test 1 | 18
Can anyone help me?
Upvotes: 0
Views: 77
Reputation: 29667
You can also use an IN
on tupples.
And a GROUP BY can be combined with a HAVING to only get those that have duplicate (name, age).
SELECT t1.Name, t2.Age
FROM YourTable2 t2
LEFT JOIN YourTable1 t1 ON t1.ID = t2.ID
WHERE (t2.ID, t2.Age) IN (
SELECT ID, Age
FROM YourTable2
GROUP BY ID, Age
HAVING COUNT(*) > 1
);
Upvotes: 0
Reputation: 3592
Try following query:
Select t1.*, t2.*
from table1 t1
join table2 t2
on t1.id = t2.id
join (select id, age
from table2
group by id, age
having count(*) > 1
) t3
on t1.id = t2.id and t2.id = t3.id and t2.age = t3.age
Upvotes: 1
Reputation: 1270401
Use exists
:
select t.*
from t
where exists (select 1
from t t2
where t2.name = t.name and t2.age = t.age and
t2.id <> t.id
);
With an index on (name, age, id)
, this should be the fastest approach.
Upvotes: 0