CODEWITHSUNDEEP
javastring-formatting
user550738
user550738

Reputation:

How to format message with argument names instead of numbers?

I have something like:

String text = "The user {0} has email address {1}."
// params = { "Robert", "[email protected]" }
String msg = MessageFormat.format(text, params);

This isn't great for me, because sometimes my translators are not sure what goes in the {0} and {1}, also it would be nice to be able to reword the messages without worrying about the order of the args.

I'd like to replace the arguments with readable names instead of numbers. Something like this:

String text = "The user {USERNAME} has email address {EMAILADDRESS}."
// Map map = new HashMap( ... [USERNAME="Robert", EMAILADDRESS="[email protected]"]
String msg = MessageFormat.format(text, map);

Is there an easy way to do this?

Thanks! rob

Upvotes: 62

Views: 59565

Answers (7)

mernst
mernst

Reputation: 8127

If use of a map is not a requirement, then you can use Java's String Templates feature. It is described in JEP 430, and it appears in JDK 21 as a preview feature. Here is an example use:

String username = "rtm";
String emailaddress = "[email protected]";
String text = STR."The user \{username} has email address \{emailaddress}."

Java's string templates are more versatile, and much safer, than features in other languagues such as C#'s string interpolation and Python's f-strings. For example, string concatenation or interpolation makes SQL injection attacks possible:

String query = "SELECT * FROM Person p WHERE p.last_name = '" + name + "'";
ResultSet rs = conn.createStatement().executeQuery(query);

but this variant (from JEP 430) prevents SQL injection:

PreparedStatement ps = DB."SELECT * FROM Person p WHERE p.last_name = \{name}";
ResultSet rs = ps.executeQuery();

Upvotes: 1

GuruKulki
GuruKulki

Reputation: 26428

You can use MapFormat for this. Find out the details here:

http://www.java2s.com/Code/Java/I18N/AtextformatsimilartoMessageFormatbutusingstringratherthannumerickeys.htm

String text = "The user {name} has email address {email}.";
Map map = new HashMap();
map.put("name", "Robert");
map.put("email", "[email protected]");

System.out.println("1st : " + MapFormat.format(text, map));

OUTPUT:

1st : The user Robert has email address [email protected].

Upvotes: 36

Andrei Ciobanu
Andrei Ciobanu

Reputation: 12838

I know my answer comes a little late, but if you still need this functionality, without the need to download a full-fledged template engine you can take a look at aleph-formatter (I am one of the authors):

Student student = new Student("Andrei", 30, "Male");

String studStr = template("#{id}\tName: #{st.getName}, Age: #{st.getAge}, Gender: #{st.getGender}")
                    .arg("id", 10)
                    .arg("st", student)
                    .format();
System.out.println(studStr);

Or you can chain the arguments:

String result = template("#{x} + #{y} = #{z}")
                    .args("x", 5, "y", 10, "z", 15)
                    .format();
System.out.println(result);

// Output: "5 + 10 = 15"

Internally it works using a StringBuilder creating the result by "parsing" the expression, no string concatenation, regex/replace is performed.

Upvotes: 1

AlikElzin-kilaka
AlikElzin-kilaka

Reputation: 36011

See StrSubstitutor from org.apache.commons.lang3:

Map valuesMap = HashMap();
valuesMap.put("animal", "quick brown fox");
valuesMap.put("target", "lazy dog");
String templateString = "The ${animal} jumped over the ${target}.";
StrSubstitutor sub = new StrSubstitutor(valuesMap);
String resolvedString = sub.replace(templateString);

// resolvedString: "The quick brown fox jumped over the lazy dog."

Upvotes: 24

Grigory Kislin
Grigory Kislin

Reputation: 18010

static final Pattern REPLACE_PATTERN = Pattern.compile("\\x24\\x7B([a-zA-Z][\\w\\x2E].*?)\\x7D");

/**
 * Check for unresolved environment
 *
 * @param str
 * @return origin if all substitutions resolved
 */
public static String checkReplacement(String str) {
    Matcher matcher = REPLACE_PATTERN.matcher(str);
    if (matcher.find()) {
        throw LOG.getIllegalArgumentException("Environment variable '" + matcher.group(1) + "' is not defined");
    }
    return str;
}

// replace in str ${key} to value
public static String resolveReplacement(String str, Map<String, String> replacements) {
    Matcher matcher = REPLACE_PATTERN.matcher(str);
    while (matcher.find()) {
        String value = replacements.get(matcher.group(1));
        if (value != null) {
            str = matcher.replaceFirst(replaceWindowsSlash(value));
        }
    }
    return str;
}

But you loose all format options (like ##.#)

Upvotes: 0

kevin cline
kevin cline

Reputation: 2736

Your question is closely related to: How to replace a set of tokens in a Java String You could use velocity or another template library. But there will be some pain because Java does not have any kind of Map literals.

Upvotes: 1

Jason S
Jason S

Reputation: 189736

Easy to make one yourself. This is what I use (the main() function is just for test code):

import java.util.HashMap;
import java.util.Map;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class StringTemplate {
    final private String template;
    final private Matcher m;
    static final private Pattern keyPattern = 
        Pattern.compile("\\$\\{([a-zA-Z][a-zA-Z0-9_]*(\\.[a-zA-Z][a-zA-Z0-9_]*)*)\\}");
    private boolean blanknull=false;

    public StringTemplate(String template) { 
        this.template=template;
        this.m = keyPattern.matcher(template);
    }

    /**
     * @param map substitution map
     * @return substituted string
     */
    public String substitute(Map<String, ? extends Object> map)
    {
        this.m.reset();
        StringBuffer sb = new StringBuffer();
        while (this.m.find())
        {
            String k0 = this.m.group();
            String k = this.m.group(1);
            Object vobj = map.get(k);
            String v = (vobj == null) 
                ? (this.blanknull ? "" : k0)
                : vobj.toString();
            this.m.appendReplacement(sb, Matcher.quoteReplacement(v));
        }
        this.m.appendTail(sb);
        return sb.toString();       
    }

    public StringTemplate setBlankNull()
    {
        this.blanknull=true;
        return this;
    }

    static public void main(String[] args)
    {
        StringTemplate t1 = new StringTemplate("${this} is a ${test} of the ${foo} bar=${bar} ${emergency.broadcasting.system}");
        t1.setBlankNull();
        Map<String, String> m = new HashMap<String, String>();
        m.put("this", "*This*");
        m.put("test", "*TEST*");
        m.put("foo", "$$$aaa\\\\111");
        m.put("emergency.broadcasting.system", "EBS");
        System.out.println(t1.substitute(m));
    }
}

Upvotes: 10

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