Reputation: 41
I currently have two tables on Bigquery where I'm trying to look up the 'english name' of a specific address. Example tables below.
Table1
Address|Value
------------------
1111,55
2222,99
8888|33
Table2
Address|Name
------------------
1111|Bob
2222|Jill
8888|Steven
Desired Result after Query
Address|Name|Value
------------------
1111|Bob|55
2222|Jill|99
8888|Steven|33
Any help to do this in BigQuery would be appreciated.
Real Query
SELECT CASE WHEN tablename.from_number = '1231231234' THEN tablename.to_number ELSE tablename.from_number END AS party,
COUNT(*) AS call_count,
tablename.caller_address AS caller_address
FROM `bigquery-database` tablename
WHERE '1231231234' in (tablename.from_number, tablename.to_number)
GROUP BY party, caller_address
ORDER by call_count DESC
In summary, I'm trying to look up caller_address' first name which resides in another table under tablename2.firstname and display it in the query output. I can't figure out how to use (join?).
Pseudo Code
SELECT CASE WHEN tablename.from_number = '1231231234' THEN tablename.to_number ELSE tablename.from_number END AS party,
COUNT(*) AS call_count,
tablename.caller_address AS caller_address,
Find where tablename.caller_address equals db.tablename2.caller_address and display first name from db.tablename2.name
FROM `bigquery-database` tablename
WHERE '1231231234' in (tablename.from_number, tablename.to_number)
GROUP BY party, caller_address
ORDER by call_count DESC
Upvotes: 0
Views: 294
Reputation: 369
I think a simple inner join is what you need.
select t1.address, t2.name, t1.value
from table1 as t1
inner join table2 as t2 on t1.address=t2.address
Upvotes: 2