Reputation: 854
I have a binairy dataframe and I would like to check whether all values in a specific row have the value 1. So for example I have below dataframe. Since row 0 and row 2 all contain value 1 in col1 till col3 the outcome shoud be 1, if they are not it should be 0.
import pandas as pd
d = {'col1': [1, 0,1,0], 'col2': [1, 0,1, 1], 'col3': [1,0,1,1], 'outcome': [1,0,1,0]}
df = pd.DataFrame(data=d)
Since my own dataframe is much larger I am looking for a more elegant way than the following, any thoughts?
def similar(x):
if x['col1'] == 1 and x['col2'] == 1 and x['col3'] == 1:
return 1
else:
''
df['outcome'] = df.apply(similar, axis=1)
Upvotes: 8
Views: 16086
Reputation: 1285
To check if multiple columns have same values, you could run this:
df[['col1','col2','col3']].apply(lambda d: len(set(d)) == 1, axis=1).nunique() == 1
Even better,
df.T.duplicated(['col1','col2','col3'])
Upvotes: 0
Reputation: 1954
This is more generic and works for any other value as well. Just replace the second == 1
with == <your value>
.
df['outcome'] = 0
df.loc[df.loc[(df.iloc[:,:-1].nunique(axis=1) == 1) \
& (df.iloc[:,:-1] == 1).all(axis=1)].index, 'outcome'] = 1
Upvotes: 1
Reputation: 11657
A classic case of all
.
(The iloc
is just there to disregard your current outcome col, if you didn't have it you could just use df == 1
.)
df['outcome'] = (df.iloc[:,:-1] == 1).all(1).astype(int)
col1 col2 col3 outcome
0 1 1 1 1
1 0 0 0 0
2 1 1 1 1
3 0 1 1 0
Upvotes: 13
Reputation: 71610
Try this instead:
df['outcome'] = df.apply(lambda x: 1 if df['col1']==1 and df['col2']==1 and df['col3']==1 else '', axis=1)
Upvotes: 1