CODEWITHSUNDEEP
python
learnerPy
learnerPy

Reputation: 123

How to incrementally print the chars in a String in Python

s = 'fo12--'
for a in s:
    a+= 1
    print(s[a])

I would expect

f  o  1  2 - -

but getting some type error. I can guess 'a' is a int here, but how can I improve this code

Upvotes: 2

Views: 115

Answers (4)

Qeek
Qeek

Reputation: 1970

Python 2/3:

Without variable:

print(' '.join("fo12--"))

With a variable:

a = "fo12--"
print(' '.join(a))

The join method iterates through object and join them with a given string.

Upvotes: 1

Jan
Jan

Reputation: 43169

It is (for Python 3):

s = 'fo12--'
for a in s:
    print(a, end = " ")

For Python 2:

s = 'fo12--'
for a in s:
    print a,

See a demo on ideone.com.

You do not need to fiddle with the a[index] syntax known from other programming languages. If you want to have the index as well, enumerate() is your friend:

s = 'fo12--'
for idx, char in enumerate(s):
    # char holds the actual character
    # idx is an increasing integer, starting from zero

Upvotes: 2

Scott Hunter
Scott Hunter

Reputation: 49803

You are using a both for the individual characters of s (your for a in s) AND as an index into that string. Either will work, but you can't use it for both at the same time.

Upvotes: 0

Nordle
Nordle

Reputation: 2981

To do what your title says would just be:

s = 'fo12--'
for i in s:
    print(i, end=' ')

But there are some fundamental problems with the code and the understanding of how it should perform (you saying that you guess 'a' is an int).

I would certainly suggest going through a Python basics program or tutorial first, it will help you get to grips with the basics and understand what is happening under the hood, so to speak.

Good luck and enjoy! :)

Upvotes: 1

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