CODEWITHSUNDEEP
pythonif-statement
Darren Weatherall
Darren Weatherall

Reputation: 11

python word from list

I created a small program that searches for a specific word in a list. It seems to work, but I'd like it to also print out the word that it found.

So far I have this, but it only returns the first word from the list, even if it isn't the word that it found.

some advice to make this work would be appreciated. Thanks,

text = 'this is a test'
words =['image', 'is']

if any(k in text for k in words):
      for k in words:
        print (k)
        print ("word found")
        break
else:
    print ("nope")

Upvotes: 0

Views: 185

Answers (7)

Tywin Lannister
Tywin Lannister

Reputation: 33

Try this.

for i in words:
    if i in text:
        print(i)

Upvotes: 0

yatu
yatu

Reputation: 88305

Note that in the loop for k in words you are simply printing all words, without checking if they are actually contained in text. You also need to split the elements in text to check if the resulting list contains k. You want to do something like:

for k in words:
    if k in text.split():
        print (k)
        print ("word found")

Output 

is
word found

The same applies to the initial condition, if you want to initially check if any words are contained in text, you need to split the words:

any(k in text.split() for k in words)

However, note that, as posted by @Austin, the most suited tool for what you're trying to do are sets. You can easily compute the common elements on both sets by computing the intersection as:

set(text.split()) & set(words)
# {'is'}

Find more about the topic in sets — Unordered collections of unique elements

Upvotes: 1

maksadbek
maksadbek

Reputation: 1592

Try this:

text = 'this is a test'
words =['image', 'is']

found = False
found_words = []

for k in words:
    if k in text:
        found_words.append(k)
        found = True

if found:
    print("words found:", found_words)
else:
    print("nope")

Will print:

words found: ['is']

Upvotes: 0

Johnny
Johnny

Reputation: 9529

Try this:

text = 'this is a test'
words =['image', 'is']

for k in [w for w in words if w in text]: 
    print (k) 
    print ("word found")

Upvotes: 0

Austin
Austin

Reputation: 26037

If you are to find common elements, I would suggest to use a set:

text = 'this is a test'
words = ['image', 'is']

print(set(words).intersection(text.split()))
# {'is'}

Upvotes: 0

RichieK
RichieK

Reputation: 554

Maybe restructure like this

text = 'this is a test'
words =['image', 'is']

words_found = [word for word in words if word in text]
if len(words_found)>0:
    print(words_found)
else:
    print("nope")

    ```

Upvotes: 0

Robin Zigmond
Robin Zigmond

Reputation: 18259

You just need to do this (one variation among many):

print(", ".join(k for k in words if k in text))

Upvotes: 1

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