Reputation: 85
I want to find a series of consecutive rows in a dataset where a condition is met the most often.
I have two columns that I can use for this; Either one with ones and zeros that alternate based on the presence or absence of a condition or a column which increments for the duration across which the desirable condition is present. I envision that I will need to use subset(),filter(), and/or rle() in order to make this happen but am at a loss as to how to get it to work.
In the example, I want to find 6 sequential rows that maximize the instances in which happens
occurs.
Given the input:
library(data.frame)
df<-data.frame(time=c(1:10),happens=c(1,1,0,0,1,1,1,0,1,1),count=c(1,2,0,0,1,2,3,0,1,2))
I would like to see as the output the rows 5 through 10, inclusive, as the data subset output, using either the happens
or count
columns since this sequence of rows would yield the highest output of happens
occurrences on 6 consecutive rows.
Upvotes: 0
Views: 50
Reputation: 27762
library(zoo)
which.max( rollapply( df$happens, 6, sum) )
#[1] 5
The fifth window of 6 rows apparently holds the maximum sum of df$happens
So the answer is row 5:10
Upvotes: 1