CODEWITHSUNDEEP
typescriptprotractor
williamtell
williamtell

Reputation: 301

TypeError: Parameter must be a string, not object

I am trying to make a function return a string but all it does is return an object. I can't use the .toString() method either.

currentEnvironment: string = "beta";
serverURL: string = this.setServerURL(this.currentEnvironment);
URL: string = this.serverURL;

async setServerURL(env: string): Promise<string> {
  const myText: string = 'https://abcqwer.com';
  return myText;
}


async login(): Promise<void> {
  console.log('Login URL is: ' + this.URL.toString());
  await browser.get(this.URL);
};

I'm getting this error:

TypeError: Parameter "url" must be a string, not object

Upvotes: 0

Views: 895

Answers (1)

Oleksii
Oleksii

Reputation: 1643

this method this.setServerURL(this.currentEnvironment) returns Promise<string> instead string. But why you need setServerURL() to be async? If you don't do any promise interaction you can re-write it:

setServerURL(env: string): string {
  const myText: string = 'https://abcqwer.com';
  return myText;
}

Imagine that you need do some promise things and your setServerURL() returns Promise<string>:

currentEnvironment = "beta"; // here typescript understand that variable has string type
serverURL: Promise<string> = this.setServerURL(this.currentEnvironment);
URL: Promise<string> = this.serverURL;

async setServerURL(env: string): Promise<string> {
  const myText: string = 'https://abcqwer.com';
  return myText; // even if 'myText' is string this method will return Promise<string> because it method has async keyword
}


async login(): Promise<void> {
  const url = await this.URL;
  console.log('Login URL is: ' + url);
  await browser.get(url);
};

Upvotes: 1

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