Reputation: 5244
Without using any extra space convert Binary Tree to Binary Search tree.I came up with the following algo but It doesn't work.
BTtoBST(node *root)
1.if the root is NULL return
2.else current=root
3.if (current->left > current) swap(current->left , current)
4.if (current->right < current) swap(current->right , current)
5.current=current->left
6 go to 3 if current!=NULL else go to 4
7.current=current->right
Thanks in advance
PS:I saw this link but was not of much help!! Convert Binary Tree -> BST (maintaining original tree shape)
Upvotes: 0
Views: 1737
Reputation: 58500
Perform a post-order (bottom up) traversal of the tree, taking the nodes that are visited and inserting them into a BST.
Does "without any extra space" preclude recursion?
If not, then something like:
# top level call passes null for bst
bt_to_bst (root, bst)
# nothing to add to bst; just return it
if null(root) -> return bst
# if this is a leaf node, stick it into the BST
if null(root->left) && null(root->right)
return bst_insert(bst, root)
# otherwise add all of left subtree into the bst and then the right tree
bst = bt_to_bst (root->left, bst);
return bt_to_bst (root->right, bst);
bt_to_bst
is a filtering operation; it takes an existing bst and returns a new one with the given node added to it.
Adding a leaf node to the bst
is safe because we will never visit it again, so we can overwrite its left
and right
pointers.
Upvotes: 0
Reputation: 4482
You can swap the nodes including subtrees (not only the node content) like in an AVL Tree http://en.wikipedia.org/wiki/AVL_tree
Just keep swapping as long as BST constraints are violated, restarting deep first search from root after each swap.
Upvotes: 1