clueless_b
clueless_b

Reputation: 9

Dereferencing pointers to make a copy of an array

I'm currently trying to copy one array to another (values 200 - 299 to be specific) while dereferencing pointers.

*point = &array2[100]; //points to location 100 in array2, which holds numbers 100-300

Couldn't I just use a for loop to start where the pointer starts, and then set both arrays equal to each other?

for(i = *point; i < 300; i++){
    array2 = array;
}

It says to dereference my pointer, so I'd use something like *(point + a number), but I'm not exactly sure what to do. An example or link to an example would be greatly appreciated

Upvotes: 0

Views: 430

Answers (1)

Sid S
Sid S

Reputation: 6125

You want something like this:

for (int *p = array1 + 200, *q = array2 + 200; p < array1 + 300; ++p, ++q)
{
    *q = *p;
}

Upvotes: 2

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