CODEWITHSUNDEEP
c
Vlad Metodiev
Vlad Metodiev

Reputation: 3

Can someone explain the logic of this bit of code?

I ran it through an IDE and the remainder values came out 3, 2, 0, 1. I understand the first remainder, but not the rest. Also, how come the loop terminates? Isn't x always going to be greater than 0, therefore continuing indefinitely? Thank you.

int x = 1023;

while (x > 0)
 {
   printf("%d", x% 10);
   x = x /10;
 }

Upvotes: 0

Views: 54

Answers (2)

aschepler
aschepler

Reputation: 72463

Note that in C, when both operands of a division have integer type, the division also has an integer type, and the value is the result of division rounded toward zero.

So in the first iteration, the statement x = x /10; changes x from 1023 to 102 (not 102.3).

Upvotes: 1

Kevin Mooney
Kevin Mooney

Reputation: 66

since you are dividing integers you are getting rounded results each time,

so each iteration of x becomes

102

10

1

Just print x each time and you will see. So 102 modulo 10 is 2

10 modul0 10 is 0

1 modulo 10 is 1

Upvotes: 0

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