CODEWITHSUNDEEP
python-3.xtkinter
user3513782
user3513782

Reputation: 83

Create a link to folder with python and tkinter

I am making an app in Python 3 (for Windows) for creating some docx files, using data from csv's, using tkinter of course for GUI. The files are saved on C:\Folder1\Folder2 Is there a way to insert a link (to a specific folder) in a message box? I mean something like a box with a message: "You can find the file here" and when the user clicks on 'here', destination folder will be opened by Windows Explorer. Or, as an alternative, the docx file itself will be opened by MS Word!

Upvotes: 1

Views: 5154

Answers (2)

Partho63
Partho63

Reputation: 3116

You can try following this process:

from tkinter import *
import os

root = Tk()
# path = 'C:\Folder Name'
path = 'C:\Folder Name\File Name.docx'

def open():
    os.startfile(path, 'open')

button = Button(root, text="Open File Direction or File", command=open)
button.pack()

root.mainloop()

Or this:

from tkinter import *
import os

def open():
    os.system("start C:/")

root = Tk()
button = Button(root, text="Open File Direction", command=open)
button.pack()
root.mainloop()

Upvotes: 2

Kamal
Kamal

Reputation: 2554

Windows has a command start to do this. You can use it like this to get same behavior as when you double-click a folder/file in Windows Explorer.

Create a button to open folder and then assign command like this:

fold_btn.config(command=lambda: os.system('start "" "{}"'.format("C:\Folder1\Folder2")))

Or Create a button to open file(docx or other) and then assign command like this:

file_btn.config(command=lambda: os.system('start "" "{}"'.format("C:\Folder1\Folder2\file.docx")))

Upvotes: 1

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