Reputation: 435
I have an excel file which I imported as a dataframe. The dataset looks like this:
rule_id reqid1 reqid2 reqid3
53139 0 0 1
51181 1 1 0
50412 0 1 1
50356 0 0 1
50239 0 1 0
50238 1 1 0
50014 1 0 1
I have converted the rule_id column into the index. I want the result to look like this:
rule_id reqid1 reqid2 reqid3 comparison1 comparison2 last_comp
53139 0 0 1 NaN NaN 100
51181 1 1 0 1.0 50.0 0
50412 0 1 1 NaN 1.0 50
50356 0 0 1 NaN NaN 100
50239 0 1 0 NaN 100.0 0
50238 1 1 0 1.0 50.0 0
50014 1 0 1 100.0 NaN 100
comparison1 column is the value comparison between reqid1 and reqid2 , comparison2 is the value comparison between reqid2 and reqid3 and last_comp is the value comparison between reqid3 and reqid4 but reqid4 is not available. So , the logic for these values is if I am comparing two columns and if both the columns has value of 0 then Null value will be captured in the new column. If the first column has 1 and the second column has 0 then 100 should be captured. If both the columns have 1 , then 1 should be captured in comparison1 column but if in reqid3 the value is 0 then in comparison2 100/2 , that is 50 should be captured. If in reqid3 , if the value is 0 then 0 should be captured in last_comp column and if the value is 1 , then 100 should be captured. But if reqid2 and reqid3 both have 1 , then 50 should be captured.
I am not able to write the code for this. Any type of help would be much appreciated.
Upvotes: 0
Views: 2081
Reputation: 86
You'll need to figure out your logic. From what you wrote, this might cover the first two extra columns, using pandas for your dataframe.
import pandas as pd
# data
d = {'rule_id': [53139,51181,50412,50356,50239,50238,50014], 'reqid1':[0,1,0,0,0,1,1], 'reqid2':[0,1,1,0,1,1,0], 'reqid3':[1,0,1,1,0,0,1]}
df = pd.DataFrame(data=d)
# reorder columns
cols = df.columns.tolist()
cols = cols[-1:]+cols[:-1]
df = df[cols]
dataframe:
rule_id reqid1 reqid2 reqid3
0 53139 0 0 1
1 51181 1 1 0
2 50412 0 1 1
3 50356 0 0 1
4 50239 0 1 0
5 50238 1 1 0
6 50014 1 0 1
then logic for new columns:
c1 = list(map(lambda a,b: a if a==b else 100*a, df.reqid1, df.reqid2 ))
df['comp1']=c1
c2 = list(map(lambda b,c,c1: b if b==c else (b if b < c else 100/(b+c1)), df.reqid2, df.reqid3, df.comp1 ))
df['comp2']=c2
# convert your zeros to Nans with numpy:
import numpy as np
comps = ['comp1', 'comp2']
df[comps] = df[comps].replace({0:np.nan})
output:
rule_id reqid1 reqid2 reqid3 comp1 comp2
0 53139 0 0 1 NaN NaN
1 51181 1 1 0 1.0 50.0
2 50412 0 1 1 NaN 1.0
3 50356 0 0 1 NaN NaN
4 50239 0 1 0 NaN 100.0
5 50238 1 1 0 1.0 50.0
6 50014 1 0 1 100.0 NaN
Upvotes: 0
Reputation: 11232
Here is some simple code to get you started:
# Compare method, gets a row containing two values as input
def compare_values(row):
a = row[0]
b = row[1]
# One of the rules
if a == 1 and b == 0:
return 100
# TODO: implement other rules
return None
# apply the `compare_values` method to all rows of ["reqid1", "reqid2"]
df["comparison1"] = df[["reqid1", "reqid2"]].apply(compare_values, axis=1)
# TODO: comparison2
I've left a couple of things for you to implement to get the exact output you want. But using this structure, you should be able to follow through.
Upvotes: 3