CODEWITHSUNDEEP
java
Weiest
Weiest

Reputation: 58

While Loop with Scanner.hasNextInt() skips last item

I was practicing using Scanner and I've encountered an strange occurance and i would like some help from the community to understand this. I've a text file with the following numbers

1,2,3,9
5,9
3

reading the text file with the following java code 

fsc = new Scanner(new File(fileName));
fsc.useDelimiter(",");
while (fsc.hasNextLine()) {
    while (fsc.hasNextInt()){
        System.out.print(fsc.nextInt() + ","); 
    }
    System.out.println();
    fsc.nextLine(); 
}

and the results always skips the last number.

1,2,3,
5,
3,

How do i make it not ignore the last item?

Edit: Some solutions calls for splinting them to an array and converting the strings to integer however I would like to explore using Scanner.nextInt() instead

Edited 2: I'm so sorry seems many misunderstood the question. What i meant was missing is the last digit of each line is missing!

Upvotes: 1

Views: 486

Answers (2)

Vikas
Vikas

Reputation: 7165

Just add one condition to check new line,

enter image description here

Upvotes: 1

George Derpi
George Derpi

Reputation: 688

This is because you removed the standard delimiters, i.e. linefeeds. You need

fsc.useDelimiter("[ ,\r\n]");

So this becomes

fsc = new Scanner(new File(fileName));
fsc.useDelimiter("[ ,\r\n]");
while (fsc.hasNextLine()) {
    while (fsc.hasNextInt()){
        System.out.print(fsc.nextInt() + ","); 
    }
    System.out.println();
    if (fsc.hasNextLine())
        fsc.nextLine(); 
}

Upvotes: 3

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