CODEWITHSUNDEEP
pythonparsingpyparsing
user2707389
user2707389

Reputation: 827

Splits based on pyparsing

so I want to do this (but using pyparsing)

Package:numpy11 Package:scipy
will be split into
[["Package:", "numpy11"], ["Package:", "scipy"]]

My code so far is 

package_header = Literal("Package:")
single_package =  Word(printables + " ") + ~Literal("Package:")
full_parser  = OneOrMore( pp.Group( package_header + single_package ) )

The current output is this

([(['Package:', 'numpy11 Package:scipy'], {})], {})

I was hoping for something like this

([(['Package:', 'numpy11'], {})], [(['Package:', 'scipy'], {})], {})

Essentially the rest of the text matches pp.printables

I am aware that I can use Words but I want to do

all printables but not the Literal

How do I accomplish this? Thank you.

Upvotes: 2

Views: 172

Answers (1)

thebjorn
thebjorn

Reputation: 27311

You shouldn't need the negative lookahead, ie. this:

from pyparsing import *

package_header = Literal("Package:")
single_package =  Word(printables)
full_parser  = OneOrMore( Group( package_header + single_package ) )

print full_parser.parseString("Package:numpy11 Package:scipy")

prints:

[['Package:', 'numpy11'], ['Package:', 'scipy']]

Update: to parse packages delimited by | you can use the delimitedList() function (now you can also have spaces in package names):

from pyparsing import *

package_header = Literal("Package:")
package_name = Regex(r'[^|]+')  # | is a printable, so create a regex that excludes it.
package = Group(package_header + package_name) 
full_parser = delimitedList(package, delim="|" )

print full_parser.parseString("Package:numpy11 foo|Package:scipy")

prints:

[['Package:', 'numpy11 foo'], ['Package:', 'scipy']]

Upvotes: 4

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