Reputation: 15
I have a simple question. How can I convert an ISO-8601 Date to an String?
I'm using a Date with the following format: 2019-02-05T08:21:15.000+01:00
and want to convert this Date Object to an String. I tried the following:
String startString = (String) jsonObjectMap2.get("created_on");
//startString = "2019-02-21T09:47:58.699004+00:00"`
DateTime start = ISODateTimeFormat.dateTimeParser().parseDateTime(startString);
DateFormat dateFormat = new SimpleDateFormat("yyyy-mm-dd'T'hh:mm:ss.SSSZ+|-hh:mm");
String formatedStartString = dateFormat.format(start);`
But Iam getting the following error:
java.lang.IllegalArgumentException: Cannot format given Object as a Date.
What is the corrrect form of the DateFormat? I hope you can help me, thank you in advance.
Upvotes: 0
Views: 2138
Reputation: 425
As Thomas alluded to in the comments, DateTime.format()
consumes a Date
object, not a DateTime
object; hence the IllegalArgumentException
. Judging by the format of your date you could try parsing your startString
using the in-built java.time.ZonedDateTime
class:
ZonedDateTime dateTime = ZonedDateTime.parse(startString) //it can parse ISO-8601 date-times
You could then format your dateTime
object using java.time.DateTimeFormatter
's static ofPattern()
method which takes a String
pattern to apply to your date-time and returns the formatted date as a String:
String formattedDateTime = dateTime.format(DateTimeFormatter.ofPattern("yyyy-MM-dd'T'hh:mm:ss.SSSZ+|-hh:mm"));
EDIT
As Basil pointed out, the OP's DateTime
object includes a time offset which is not necessarily a time zone offset--as is represented by the ZonedDateTime
class. Thus the most appropriate class to use in this scenario is OffsetDateTime
which provides the same capabilities but is more suited for the given use case. See Basil Bourque's answer
Upvotes: 1
Reputation: 338276
java.time.OffsetDateTime.parse( "2019-02-21T09:47:58.699004+00:00" )
What class is DateTime
? If you are using Joda-Time, know that the Joda-Time project is now in maintenance-mode. Its creator, Stephen Colbourne, went on to lead JSR 310 and implement the java.time classes built into Java.
Your input string is in standard ISO 8601 format. The java.time classes use the ISO 8601 formats by default when parsing/generating strings.
String input = "2019-02-21T09:47:58.699004+00:00" ; // Standard ISO 8601 format.
OffsetDateTime
Your input string indicates an offset-from-UTC but not a time zone. So the appropriate class to represent this value is OffsetDateTime
.
OffsetDateTime odt = OffsetDateTime.parse( input ) ;
The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date
, Calendar
, & SimpleDateFormat
.
To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.
The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.
You may exchange java.time objects directly with your database. Use a JDBC driver compliant with JDBC 4.2 or later. No need for strings, no need for java.sql.*
classes.
Where to obtain the java.time classes?
The ThreeTen-Extra project extends java.time with additional classes. This project is a proving ground for possible future additions to java.time. You may find some useful classes here such as Interval
, YearWeek
, YearQuarter
, and more.
Upvotes: 2
Reputation: 61
I have found the following to work for me
DateTimeFormatter dateTimeFormatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS[XXX]");
String formatted = zonedDateTime.format(dateTimeFormatter);
Upvotes: 0
Reputation: 15
I am not certain that this will solve your problem, But mm should be uppercase i.e MM, Because MM describes months while mm describes minutes.
see the following code:
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSSZ+|-
hh:mm");
Upvotes: 0