CODEWITHSUNDEEP
pythonturtle-graphicstic-tac-toepython-turtle
twinnxx
twinnxx

Reputation: 49

Python turtle tic tac toe

I'm new to python and I programed a tic tac toe with an AI that plays against you. Everything is working but I used textboxes to inform the AI what the player chose. Now I want to upgrade my game so that the player can click on the box he wants to fill instead of typing it in the textbox. My idea was to use onscreenclick() but I'm having some issues. onscreenclick() returns the coordinates that have been clicked on the canvas and I want to use a function to determine in which box the player clicked.

I got this:

from turtle import * 

def whichbox(x,y): #obviously i got 9 boxes but this is just an example for box 1
    if x<-40 and x>-120:
        if y>40 and y<120:
            return 1
        else:
            return 0
    else:
        return 0

box=onscreenclick(whichbox)
print(box)

It's obvious that I want box to be 0 or 1 in this case but instead the value of box is None. Does anyone know how to fix this? It has to do something with the variable box because I if replace return 1 with print("1") it works. I assume that the variable gets defined to quickly.

The second question that I have is if its possible pause the programm until the player clicked on a box but its more important to look at the first problem first.

Upvotes: 4

Views: 719

Answers (2)

cdlane
cdlane

Reputation: 41872

Here's a stripped down example from the code I linked to in my comment. If you click on a square, it will print to the console window its number, from 0 to 8:

from turtle import Turtle, mainloop

CURSOR_SIZE = 20
SQUARE_SIZE = 60

def drawBoard():
    for j in range(3):
        for i in range(3):
            square = Turtle('square', visible=False)
            square.shapesize(SQUARE_SIZE / CURSOR_SIZE)
            square.fillcolor('white')
            square.penup()
            square.goto((i - 1) * (SQUARE_SIZE + 2), (j - 1) * (SQUARE_SIZE + 2))

            number = j * 3 + i
            square.onclick(lambda x, y, number=number: whichsquare(number))
            square.showturtle()

def whichsquare(number):
    print(number)

drawBoard()

mainloop()

There is no position decoding involved -- we let turtle handle that for us.

Upvotes: 2

aargon
aargon

Reputation: 126

Assuming you have named your Screen() in the turtle module, you should then put

screen.onscreenclick(whichbox)

instead of:

onscreenclick(whichbox)

Example:

from turtle import Turtle, Screen
turtle = Turtle()
screen = Screen()

def ExampleFunction():
    return 7

screen.onscreenclick(ExampleFunction)

Furthermore, jasonharper is correct when he says the onscreenclick() function is unable to return any value. As such, you can include a print function within your function whichbox() in order to print out a value, like:

def whichbox(x,y): 
    if x<-40 and x>-120:
        if y>40 and y<120:
            print(1)
            return 1
        else:
            print(0)
            return 0
    else:
        print(0)
        return 0

Alternatively, if you wanted to keep the print statement outside of whichbox(), you could also do the following:

screen.onscreenclick(lambda x, y: print(whichbox(x, y)))

which creates a lambda function that gives (x, y) from onscreenclick() to a print statement containing whichbox().

Upvotes: 2

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