Reputation: 23
I wanted to understand how the inline member variable work while accessing it through a const member variable. Each time I try doing so, I get an error!
This is what I am trying
#include <iostream>
#include <string>
using namespace std;
class A{
public:
A()
{
_uuid = 0;
}
~A();
void setUUID(int n) { _uuid = n; }
inline int getUUID(){ return _uuid;} const
int getUUID1() const { return _uuid;}
int getUUIDsmart()const
{
return _uuid;
}
private:
int _uuid;
};
class B {
public:
B(){}
~B();
void fun1(const A *obj)
{
cout<<obj->getUUIDsmart()<<endl; //works fine
cout<<obj->getUUID1()<<endl; //works fine
cout<<obj->getUUID()<<endl; //error
A *obj1 = const_cast<A *>(obj);
cout<<obj1->getUUID()<<endl; //works fine
}
};
int main()
{
B *b = new B;
A *a = new A;
a->setUUID(12);
b->fun1(a);
}
I am able to get my code work through
const_cast
But I am interested in knowing why do i get an error in the inline function if I try accessing it through a const member function?
My bad. I had the placement of const messed up! Thanks to @bruno
inline int getUUID() const { return _uuid; }
//correct syntax. i placed the const at the end
Upvotes: 2
Views: 284
Reputation: 32586
[note : I use the first version of the question]
you place wrongly your const :
inline int getUUID(){ return _uuid;} const
int getUUID1(){ return _uuid;} const
int getUUIDsmart()const
is in fact
inline int getUUID(){ return _uuid;}
const int getUUID1(){ return _uuid;}
const int getUUIDsmart()const
I just moved the const on the right line for readability reason
You wanted
inline int getUUID() const { return _uuid;}
int getUUID1() const{ return _uuid;}
in your version none of getUUID1 nor getUUID are const so you cannot apply them on a const instance
There is no link at all with the fact your methods are inline or not.
Note :
cout<<obj->getUUID1()<<endl; //works fine
it doesn't
Upvotes: 3