Reputation: 2180
To be specific, the problem is:
Given array of denominations coins[]
, array of limit for each coins limits[]
and number amount
, return minimum number of coins needed, to get the amount
, or if it's not possible return null. Additionally fill array change
with number of each coin used in the solution.
This is my solution:
public static int? Dynamic(int amount, int[] coins, int[] limits, out int[] change)
{
int[] minCoins = new int[amount + 1];
int[,] coinsUsedToAmount = new int[coins.Length, amount + 1];
minCoins[0] = 1;
for (int j = 0; j < amount; ++j)
{
if (minCoins[j] == 0)
{
continue;
}
for (int i = 0; i < coins.Length; ++i)
{
if (coinsUsedToAmount[i, j] >= limits[i])
{
continue;
}
int currAmount = j + coins[i];
if (currAmount <= amount
&& (minCoins[currAmount] == 0
|| minCoins[currAmount] > minCoins[j] + 1))
{
minCoins[currAmount] = minCoins[j] + 1;
for (int k = 0; k < coins.Length; ++k)
{
coinsUsedToAmount[k, currAmount] = coinsUsedToAmount[k, j];
}
coinsUsedToAmount[i, currAmount] += 1;
}
}
}
if (minCoins[amount] == 0)
{
change = null;
return null;
}
change = new int[coins.Length];
for(int i = 0; i < coins.Length; ++i)
{
change[i] = coinsUsedToAmount[i, amount];
}
return minCoins[amount] - 1;
}
But it doesn't work in general.
My issue is that for example in such case:
amount = 141,
coins = new int[] { 2, 137, 65, 35, 30, 9, 123, 81, 71 }
limits = new int[] { 1, 1, 1, 1, 1, 1, 1, 1, 1 }
Optimal solution is:
change = new int[] { 1, 0, 1, 1, 1, 1, 0, 0, 0 }
And my algorithm gives null
as the result. In the other words it fails, whenever on some way up I would have to use less optimal solution than it's possible, and then, at the end, I don't have necessary coins.
So, in this example my algorithm makes a mistake in following step:
minCoins[132] = (9 + 123) // 2 coins
But it should be:
minCoins[132] = (2 + 65 + 35 + 30) // 4 coins
because then I can use 9 and have 141.
I have been coming back to this problem for a few weeks now and I still can't solve it. I had seen numerous solutions to similar problems on this and other sites, but none of them helped me.
Upvotes: 5
Views: 5413
Reputation: 2180
Friend of mine helped me solve it. The idea is that we go from the amount
to 0
and try to use all the nominal of each coins possible - that way we won't end up using certain coins at the beginning, and then we wouldn't have possibility to use them for amount.
/// <summary>
/// Method used to resolve minimum change coin problem
/// with constraints on the number of coins of each type.
/// </summary>
/// <param name="amount">Amount of change to make, e.g. 13</param>
/// <param name="coins">Available types of coins, e.g. {1, 2, 3, 5}</param>
/// <param name="limits">Number of available coins of specific type, e.g. {1, 5, 3, 2}</param>
/// <param name="change">Number of coins of each type used to make the change, e.g. {0, 0, 1, 2}</param>
/// <returns>
/// Minimal number of coins needed to make the change
/// (equal to sum of change array entries), e.g. 3
/// </returns>
/// <remarks>
/// coins[i] - nominal value of the coin of i-th type
/// limits[i] - number of available coins of i-th type (denomination)
/// change[i] - number of coins of i-th type used in the solution
///
/// If available `coins` and `limits` does not allow to make provided `amount` of change
/// then `change` should be set to `null`, and method should also return `null`.
///
/// Tips/requirements:
/// The size of work memory of the algorithm should (must) be
/// proportional to the value of product: `amount*(coins.Length)`
/// (that is O(amount*(coins.Length))
/// </remarks>
public static int? Dynamic(int amount, int[] coins, int[] limits, out int[] change)
{
int[][] coinsUsed = new int[amount + 1][];
for (int i = 0; i <= amount; ++i)
{
coinsUsed[i] = new int[coins.Length];
}
int[] minCoins = new int[amount + 1];
for (int i = 1; i <= amount; ++i)
{
minCoins[i] = int.MaxValue - 1;
}
int[] limitsCopy = new int[limits.Length];
limits.CopyTo(limitsCopy, 0);
for (int i = 0; i < coins.Length; ++i)
{
while (limitsCopy[i] > 0)
{
for (int j = amount; j >= 0; --j)
{
int currAmount = j + coins[i];
if (currAmount <= amount)
{
if (minCoins[currAmount] > minCoins[j] + 1)
{
minCoins[currAmount] = minCoins[j] + 1;
coinsUsed[j].CopyTo(coinsUsed[currAmount], 0);
coinsUsed[currAmount][i] += 1;
}
}
}
limitsCopy[i] -= 1;
}
}
if (minCoins[amount] == int.MaxValue - 1)
{
change = null;
return null;
}
change = coinsUsed[amount];
return minCoins[amount];
}
Upvotes: 6