CODEWITHSUNDEEP
pythonjson
gagan patel
gagan patel

Reputation: 1

json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0) how to resolve?

import json
filename = 'username.json'
try:
    with open(filename) as fo:
        username = json.loads(fo)
except FileNotFoundError:
    user = input("Tell me your username?  ")
    print("I'll remember you next time! " + user + " !")
    with open(filename ,'w') as fo:
        json.dump(user ,fo)
else:
    print("So we meet again " +userame +" !")

output:

PS C:\Users\gagan\Desktop\python crash course> python jsonfile.pyTraceback (most recent call last):
  File "jsonfile.py", line 5, in <module>
    username = json.loads(str(fo))
  File "C:\Users\gagan\AppData\Local\Programs\Python\Python37-32\lib\json\__init__.py", line 348, in loads
    return _default_decoder.decode(s)
  File "C:\Users\gagan\AppData\Local\Programs\Python\Python37-32\lib\json\decoder.py", line 337, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "C:\Users\gagan\AppData\Local\Programs\Python\Python37-32\lib\json\decoder.py", line 355, in raw_decode
    raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

Upvotes: 0

Views: 189

Answers (1)

Nikolas Stevenson-Molnar
Nikolas Stevenson-Molnar

Reputation: 4680

You're passing the file handle to json.loads, which expects a string. Instead you either want to use json.load (no 's'):

username = json.load(fo)

Or use json.loads (with the 's' at the end, which stands for 'string') with the file contents:

username = json.loads(fo.read())

Upvotes: 2

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