CODEWITHSUNDEEP
pythonlistdictionarypython-3.7
Max16hr
Max16hr

Reputation: 468

Python: Set list elements as dict values

Short question and probably short answer, but I do not get it^^

d = {'a' : 0, 'b' : 0, 'c' : 0, 'd' : 0}
l = [1, 2, 3, 4]

I want to set the list values to the dictionary such that

d = {'a' : 1, 'b' : 2, 'c' : 3, 'd' : 4}

Of course

d['a'], d['b'], d['c'], d['d'] = l

will make it, but that cant be the right way to do it. What if I have 50 values ... A loop that zips d and l will work as well.

But there is something short like d.values = l, isn't it?

Thanks for helping! :)

Edit: I’m using Python 3.7, so the dict is ordered by insertion.

Upvotes: 0

Views: 13215

Answers (2)

chepner
chepner

Reputation: 532448

No, there is no short-cut. You need to use dict.update with a list of pairs.

d.update(zip(d, l))

Upvotes: 13

Jab
Jab

Reputation: 27515

In Python 3.7+ dicts are ordered in the order the items are inserted. Therefore the following would be correct.

d = {'a' : 0, 'b' : 0, 'c' : 0, 'd' : 0}
for i, k in enumerate(d.keys(), 1):
    d[k] = i

Or you could use something like the following:

d['a'], d['b'], d['c'], d['d'] = range(1,5) #or 1, 2, 3, 4

Edit

One liner for you using a dict comprehension:

d = {key: val for val, key in enumerate(d.keys(), 1)}

Upvotes: 1

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