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javascriptloopstimer
MorganFR
MorganFR

Reputation: 341

setTimeout in for loop (1 timeout then loop at once) (double loop)

I followed the answer to this post, however, this doesn't seem to work for me. I have a first 2 dimensional array, I want to timeout between every outer loop and not timeout in the outer loop.

Here's a snippet of this Fiddle showing one of the three ways I tried, from the aforementioned question as well as this one (cf. case 1, 2 and 3). 

    var data = [
                [
                    ["data[0][0]"],  
                    ["data[0][1]"]
                ],
                [
                    ["data[1][0]"],
                    ["data[1][1]"]
                ],
                [
                    ["data[2][0]"],
                    ["data[2][1]"]
                ]
            ];	

    var delay = 1000;
    
        function doSomething(i) {
    	setTimeout(function() {
      	for(let j = 0; j < data[i].length; j++) {
        console.log(data[i][j]);
        $('#result').html($('#result').html() + data[i][j]);
        }
      }, delay);
    }
    
    for(let i = 0; i < data.length; i++) {
    	doSomething(i);
    }
    <script src="http://code.jquery.com/jquery-1.9.1.js"></script>
    <div id="result"></div>

More questions/answers on the subject tend to yield the same result so I am at a loss.

Upvotes: 3

Views: 485

Answers (2)

Shidersz
Shidersz

Reputation: 17190

Another solution for this problem (using a recursive idea) is to implement a method that call to itself every 1 second until reach the last iteration (break condition), when the index of the outter array is equal to his length:

var data = [
  [["data[0][0]"], ["data[0][1]"]],
  [["data[1][0]"], ["data[1][1]"]],
  [["data[2][0]"], ["data[2][1]"]]
];

function doSomething(i, delay)
{
    // Break condition.

    if (i >= data.length)
        return;

    // Print the inner array.

    data[i].forEach(x =>
    {
        console.log(x);
        $('#result').html($('#result').html() + x);
    });

    // Call to itself after some time to execute next iteration.

    setTimeout(() => doSomething(i + 1, delay), delay);
}

// Start the procedure.

doSomething(0, 1000);
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<div id="result"></div>

Upvotes: 2

David784
David784

Reputation: 7464

The problem is in how the setTimeout works. It's not a sleep command where it stops the for loop. Rather, it is blazing through the initial for loop, and starting three timers at roughly the same time, to last for one second each. That means they also all end at about the same time.

You can get your desired outcome by doing something more like this (notice the i*delay for the timer on the setTimeout. That way your first timer is for 0ms, second for 1000ms, third for 2000ms, and you get the staggered results you're after.

var data = [
  [
    ["data[0][0]"],
    ["data[0][1]"]
  ],
  [
    ["data[1][0]"],
    ["data[1][1]"]
  ],
  [
    ["data[2][0]"],
    ["data[2][1]"]
  ]
];

var delay = 1000;

function doSomething(i) {
  setTimeout(function () {
    for (let j = 0; j < data[i].length; j++) {
      console.log(data[i][j]);
      $('#result').html($('#result').html() + data[i][j]);
    }
  }, i*delay);
}

for (let i = 0; i < data.length; i++) {
  doSomething(i);
}
    <script src="http://code.jquery.com/jquery-1.9.1.js"></script>
    <div id="result"></div>

Upvotes: 2

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