CODEWITHSUNDEEP
gitshellmakefile
Teererai Marange
Teererai Marange

Reputation: 2132

make: trying to pass git_commit_id to variable in make_file

I am trying to get the git commit id and pass it to a script as a command line value to a file that I've compiled in cpp. To this end I've written the following snipped it my makefile. 

%.cool_stuff:  %.c cool_stuff.cpp 
    $(CXX) $(OPT) cool_stuff.cpp -include $< -o $@ -l sqlite3 
    git_commit_id=$(shell $$(git rev-parse HEAD))
    ./$@ 1 $(git_commit_id)

The problem is that when I run the code, part of the output contains the statement:

/bin/sh: 1: cdc8bdff6ccbc9dd14da68343fe4809f02cbe07e: not found

so that nothing ends up getting passed for $(git_commit_id) to the last line of the snippet.

please advise.

Upvotes: 1

Views: 151

Answers (2)

jthill
jthill

Reputation: 60323

Waayyyyy too many layers of interpreter invocation. Try

%.cool_stuff:  %.c cool_stuff.cpp 
    $(CXX) $(OPT) cool_stuff.cpp -include $< -o $@ -l sqlite3
    git_commit_id=`git rev-parse HEAD`; \
    ./$@ 1 $$git_commit_id

(edit: corrections from comments; also: note that markdown formatting eats tabs, don't c&p without replacing leading spaces with leading tabs).

Upvotes: 3

Teererai Marange
Teererai Marange

Reputation: 2132

Surround the $(shell..) command in a call to eval as shown below 

$(eval git_commit_id=$(shell git rev-parse HEAD))

Upvotes: 0

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