Reputation: 4376
I have an array like this:
['one','three','two','four']
I have a array of hash like this:
[{'three' => {..some data here..} }, {'two' => {..some data here..} }, {:total => some_total }] # etc...
I want to sort the array of hashes by the first array. I know I can do:
array_of_hashes.sort_by{|k,v| k.to_s} to sort them and it will sort by the key
( and the .to_s to convert :total to a string )
How can I make this happen?
Edit:
I was incorrect about how this is setup, it is actually like this:
{'one' => {:total => 1, :some_other_value => 5}, 'two' => {:total => 2, :some_other_value => 3} }
If I need to put this in a new question, just let me know and I will do that.
Thank you
Upvotes: 2
Views: 1908
Reputation: 2712
similar to ctcherry answer, but using sort_by.
sort_arr = ['one','three','two','four']
hash_arr = [{'three' => {..some data here..} }, {'two' => {..some data here..} }]
hash_arr.sort_by { |h| sort_arr.index(h.keys.first) }
Upvotes: 6
Reputation: 28574
The index
method of Array is your friend in this case:
sort_list = ['one','three','two','four']
data_list = [{'three' => { :test => 3 } }, {'two' => { :test => 2 } }, {'one' => { :test => 1 } }, {'four' => { :test => 4 } }]
puts data_list.sort { |a,b|
sort_list.index(a.keys.first) <=> sort_list.index(b.keys.first)
}.inspect
Resulting in, the same order as the source array:
[{"one"=>{:test=>1}}, {"three"=>{:test=>3}}, {"two"=>{:test=>2}}, {"four"=>{:test=>4}}]
Upvotes: 0