CODEWITHSUNDEEP
php
Karan
Karan

Reputation: 268

Unable to produce variable output of type string in multi-lines in PHP

I don't know the correct wording for this issue I am having.

I have a object returned from the database like below:

$pProvisioningFileData->m_fileContent = # Placeholders identified by '${}' 
will be replaced during the provisioning
# process, only supported placeholders will be processed.
Dcm.SerialNumber = ${unit.serial_number}
Dcm.MacAddress = ${unit.mac_address}
Dcm.MinSeverity = "Warning"
Cert.TransferHttpsCipherSuite = "CS1"
Cert.TransferHttpsTlsVersion = "TLSv1"
Cert.MinSeverity = "Warning";

The curly brackets are placeholders, the problem I am facing is that when I try output all the content using either echo or print_r, all the content prints in one line however I want to display the content in the same sequence as above.

I tried using var_dump but it also gives some extra info like length and type of variable which I don't want.

So is there a simple way of doing this without using an array?

Upvotes: 0

Views: 31

Answers (2)

Jc Nolan
Jc Nolan

Reputation: 470

It is difficult from your question to understand exactly what you are wanting to do, but there are three ways you can print out the contents of an object. The third here, looping members, will give you more control and you can add a switch statement or other formatting to output precisely what you desire:

class unit {

    var $serial_number;
    var $mac_address;
}

    $test = new unit;
    $test->serial_number = "999";
    $test->mac_address = "999.999.999.999";

    /* Method 1 - print_r */

    print_r($test); 
    print "\n\n";

    /* Method 1 - var_dump */

    var_dump($test); 
    print "\n\n";

    /* Method 3 - looping members */

    foreach ($test as $memberName => $member) 
    {
        print "{$memberName}: {$member}\n";
    }

Upvotes: 0

Maciej Kogut
Maciej Kogut

Reputation: 71

If you are outputting to browser then wrapping your var_dump in html <pre> tags is quick solution. If you outputting to console then I advise you to install some advanced debuging software. Xdebug comes to mind.

Upvotes: 2

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