CODEWITHSUNDEEP
pythonpython-3.xstring
cardamom
cardamom

Reputation: 7421

match a string followed by a number with string methods only

So I have written a lot of code and so far avoided importing or using regex and would prefer to keep it that way if possible.

Have a list which looks like this:

mylist = ["dog", "dogs", "dogs75", "75dogs", "cats75"]

I can get the indexes of various matched elements like this:

>>> [i for i, j in enumerate(mylist) if "cat" in j]
[4]
>>> [i for i, j in enumerate(mylist) if "dog" in j]
[0, 1, 2, 3]
>>>

The one I'm actually looking for is "dogs75", actually any string which contains an integer at the end.

Can this be done without importing re?

Upvotes: 1

Views: 40

Answers (3)

Merig
Merig

Reputation: 2011

[s for s in mylist if s[-1].isdigit()]

should give you the list you want

Upvotes: 0

liamhawkins
liamhawkins

Reputation: 1371

You can use isdecimal() to check the last character:

>>> mylist = ["dog", "dogs", "dogs75", "75dogs", "cats75"]
>>> [i for i, j in enumerate(mylist) if j[-1].isdecimal()]
[2, 4]

You could also replace isdecimal with isdigit or isnumeric if you are expected number-like characters that aren't the digits 0-9

Upvotes: 1

yatu
yatu

Reputation: 88236

You can use a list comprehension and check if the last character of each string is numeric:

[ix for ix, i in enumerate(mylist) if i[-1].isnumeric()]
# [2, 4]

Upvotes: 1

Related Questions