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c#arrays
Fidsah
Fidsah

Reputation: 859

C# Creating an array of arrays

I'm trying to create an array of arrays that will be using repeated data, something like below:

int[] list1 = new int[4] { 1, 2, 3, 4 };
int[] list2 = new int[4] { 5, 6, 7, 8 };
int[] list3 = new int[4] { 1, 3, 2, 1 };
int[] list4 = new int[4] { 5, 4, 3, 2 };

int[,] lists = new int[4, 4] {  list1 ,  list2 ,  list3 ,  list4  };

I can't get it to work and so I'm wondering if I'm approaching this wrong.

What I'm attempting to do is create some sort of method to create a long list of the values so I can process them in a specific order, repeatedly. Something like,

int[,] lists = new int[90,4] { list1, list1, list3, list1, list2, (and so on)};

for (int i = 0; i < 90; ++i) {
   doStuff(lists[i]);
}

and have the arrays passed to doStuff() in order. Am I going about this entirely wrong, or am I missing something for creating the array of arrays?

Upvotes: 61

Views: 191316

Answers (5)

Richard Collette
Richard Collette

Reputation: 5713

The following will give you an array in the iterator variable of foreach

int[][] ar =
{
    new []{ 50, 50, 1 },
    new []{ 80, 40, 2 },
    new []{ 10, 60, 3 },
    new []{ 51, 38, 4 },
    new []{ 48, 38, 5 }
};

Upvotes: 0

Robert Quinn
Robert Quinn

Reputation: 589

This loops vertically but might work for you.

int rtn = 0;    
foreach(int[] L in lists){
    for(int i = 0; i<L.Length;i++){
          rtn = L[i];
      //Do something with rtn
    }
}

Upvotes: 0

Noldorin
Noldorin

Reputation: 147451

I think you may be looking for Jagged Arrays, which are different from multi-dimensional arrays (as you are using in your example) in C#. Converting the arrays in your declarations to jagged arrays should make it work. However, you'll still need to use two loops to iterate over all the items in the 2D jagged array.

Upvotes: 9

Suroot
Suroot

Reputation: 4423

The problem is that you are attempting to define the elements in lists to multiple lists (not multiple ints as is defined). You should be defining lists like this.

int[,] list = new int[4,4] {
 {1,2,3,4},
 {5,6,7,8},
 {1,3,2,1},
 {5,4,3,2}};

You could also do 

int[] list1 = new int[4] { 1, 2, 3, 4};
int[] list2 = new int[4] { 5, 6, 7, 8};
int[] list3 = new int[4] { 1, 3, 2, 1 };
int[] list4 = new int[4] { 5, 4, 3, 2 };

int[,] lists = new int[4,4] {
 {list1[0],list1[1],list1[2],list1[3]},
 {list2[0],list2[1],list2[2],list2[3]},
 etc...};

Upvotes: 12

Sean
Sean

Reputation: 62532

What you need to do is this:

int[] list1 = new int[4] { 1, 2, 3, 4};
int[] list2 = new int[4] { 5, 6, 7, 8};
int[] list3 = new int[4] { 1, 3, 2, 1 };
int[] list4 = new int[4] { 5, 4, 3, 2 };

int[][] lists = new int[][] {  list1 ,  list2 ,  list3 ,  list4  };

Another alternative would be to create a List<int[]> type:

List<int[]> data=new List<int[]>(){list1,list2,list3,list4};

Upvotes: 84

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