Reputation:
I am trying to pivot my current two column dataframe which currently looks like this:
one two
a 12
b 32
c 12
I want to pivot this resulting in neither column becoming the index. My expected result is:
a b c
12 32 12
a, b, and c are the new columns. 12, 32, 12 are the values in the row.
Thanks
Upvotes: 10
Views: 12865
Reputation: 59579
Giving everything the same index with .pivot_table
df.pivot_table(columns='one', index=df.index//len(df), values='two').rename_axis(None, axis=1)
#or with pivot
df = df.pivot(columns='one', index=df.index//len(df)).rename_axis([None, None], axis=1)
df.columns = [y for _,y in df.columns]
a b c
0 12 32 12
Upvotes: 1
Reputation: 153500
Use set_index
to move column 'one' into the index, then use T
to transpose.
a.set_index('one').T
Output:
one a b c
two 12 32 12
Info:
<class 'pandas.core.frame.DataFrame'>
Index: 1 entries, two to two
Data columns (total 3 columns):
a 1 non-null int64
b 1 non-null int64
c 1 non-null int64
dtypes: int64(3)
memory usage: 28.0+ bytes
None
Upvotes: 11
Reputation: 1489
If this is your input:
a = pd.DataFrame([("a", 12), ("b", 32), ("c", 12)], columns=["one", "two"])
one two
0 a 12
1 b 32
2 c 12
Then a.transpose()
results in this:
0 1 2
one a b c
two 12 32 12
Is this what you were looking for?
Upvotes: 4