CODEWITHSUNDEEP
pythonpython-2.7
luciferchase
luciferchase

Reputation: 559

How to concatenate all the numbers in a list?

For clarification, I don't just only want a random letter word. I need the random numbers in my code later on also.

I made the following code which gives a random 7 letter word.
Here is the code:-

import random
key_num = []
for initial_num in range(7):
    key_num.append(random.randrange(1,26))
def value(n):
    return (chr(int(n) + 64))
print value(key_num[0]) + value(key_num[1]) + value(key_num[2]) + value(key_num[3]) + value(key_num[4]) + value(key_num[5]) + value(key_num[6])

My question is there any better way to concatenate the word using the random numbers?

Upvotes: 0

Views: 1094

Answers (5)

Finlay McWalter
Finlay McWalter

Reputation: 1342

You've tagged your question Python2.7. If you can use Python3 instead, you can use random.choices to make things rather simple:

from string import ascii_lowercase
from random import choices

print ("".join(choices(ascii_lowercase,k=7)))

If you're stuck in Python2, you can implement a (simplistic) random.choices thus:

from random import choice

def choices(s,k=1):
  return [choice(s) for _ in xrange(k)]

Upvotes: 1

hiro protagonist
hiro protagonist

Reputation: 46899

this is a way:

from random import randrange
from string import ascii_lowercase

def random_str(length=7):
    return ''.join(ascii_lowercase[randrange(len(ascii_lowercase))] for _ in range(length))

ascii_lowercase is just 'abcdefghijklmnopqrstuvwxyz'; i select a random entry from that and join the single letters with str.join.

...actually random.choice is better suited for that. see this answer.

Upvotes: 0

elemakil
elemakil

Reputation: 3811

There are many different ways to solve this and also improve your code. You should definitely checkout str.join and list comprehensions.

If you want to stick to your original code as much as possible, how about this basic solution:

import random
key_num = []
for initial_num in range(7):
    key_num.append(random.randrange(1,26))
def value(n):
    return (chr(int(n) + 64))

# so far unchanged, here comes the new bit:
print ''.join(value(k) for k in key_num)

Upvotes: 1

Joran Beasley
Joran Beasley

Reputation: 114038

import string
word = "".join(random.choice(string.ascii_lowercase) for _ in range(string_length)]

Is how i would make a random string

Upvotes: 2

skaul05
skaul05

Reputation: 2344

You can achieve concatenation in a single for loop.
Try Below Code:

import random
key_num = []
for initial_num in range(7):
    key_num.append(random.randrange(1,26))
def value(n):
    return (chr(int(n) + 64))
final_string = ""
for i in range(7): # Range of Numbers you want
    final_string += value(key_num[i]) # Concatenate random character
print final_string

Upvotes: 0

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