CODEWITHSUNDEEP
phpregexpreg-match
Norman
Norman

Reputation: 6365

PHP preg_match year validation 1900 to 2019

I'm trying to validate a date in dd-mm-yyyy format, where the year should be between 1900 to 2019.

The day and month part work fine, but i'm failing with the year part. Can you pls help?

$date="31-12-2020";

if (preg_match("/^(0[1-9]|[1-2][0-9]|3[0-1])-(0[1-9]|1[0-2])-(19[0-9]{2}|20([0-1]|[0-9]){2})$/",$date)) {
        echo 'True';
    return true;
} else {
        echo 'False';
    return false;
}

Upvotes: 0

Views: 1339

Answers (3)

Pushpesh Kumar Rajwanshi
Pushpesh Kumar Rajwanshi

Reputation: 18357

Your current year part 20([0-1]|[0-9]){2} for handling years 2000 to 2019 just needs little modification to make it correct. Third digit in year part can only be 0 or 1 hence it can be written as [01] and fourth digit can be any hence can be written as [0-9] and that gives us 20[01][0-9]. Following is your modified regex you can use,

^(0[1-9]|[1-2][0-9]|3[0-1])-(0[1-9]|1[0-2])-(19[0-9]{2}|20[01][0-9])$

Demo

Also, since you're just validating your text, you can convert all groups as non-capturing groups to make it little better performance wise.

^(?:0[1-9]|[1-2][0-9]|3[0-1])-(?:0[1-9]|1[0-2])-(?:19[0-9]{2}|20[01][0-9])$

Demo with non-capturing group

Upvotes: 0

Milan Rilex Ristic
Milan Rilex Ristic

Reputation: 507

This is complete script that you need; function will return true or false if given date is in range:

http://sandbox.onlinephpfunctions.com/code/c0e8108319a24ae5ecf993bb940e1f30aab53fc7

$start_date = '01-01-1900';
$end_date = '01-01-2019';
$date_from_user = '01-01-2018';

check_in_range($start_date, $end_date, $date_from_user);


function check_in_range($start_date, $end_date, $date_from_user,$format='d-m-Y')
{
  // Convert to timestamp
  $start_ts = DateTime::createFromFormat($format,$start_date);
  $end_ts = DateTime::createFromFormat($format,$end_date);
  $user_ts = DateTime::createFromFormat($format,$date_from_user);

  // Check that user date is between start & end
  return (($user_ts >= $start_ts) && ($user_ts <= $end_ts));
}

Upvotes: 5

Hasitha Amarathunga
Hasitha Amarathunga

Reputation: 2005

This think year expression should as below

19[0-9][0-9] | 20[0-1][0-9]

Upvotes: -1

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