CODEWITHSUNDEEP
javac#mathnumeric
Hostd
Hostd

Reputation: 25

Java to C# - BigInt.modPow

Okay so I'm trying to convert a method from Java to c#, however modPow in C# takes 3 arguments, where as in Java it only takes 2? How can I convert the following to C# -

BigInteger var6 = var5.modPow(var1, var2);

Tried the following but it returns exceptions -

BigInteger var6 = var5.ModPow(var1, var2);

stating - DivideByZero Exception, ArgumentOutOfRangeException..

which is obviously due to the fact there's only 2 arguments instead of 3, however I don't want to add a blank argument as it may cause the functionality to not work correctly.

Upvotes: 0

Views: 113

Answers (2)

DavidG
DavidG

Reputation: 119076

In Java the modPow method is exposed against an instance of BigInteger whereas in C# it is a static method on the BigInteger class. See the docs for ModPow. This means you need to do this:

BigInteger var6 = BigInteger.ModPow(var5, var1, var2);

Upvotes: 1

Joseph Sible-Reinstate Monica
Joseph Sible-Reinstate Monica

Reputation: 48647

this is the "missing" argument. When you'd do x.modPow(y, z) in Java, do ModPow(x, y, z) in C#.

Upvotes: 1

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