CODEWITHSUNDEEP
python
Simão
Simão

Reputation: 117

Learning Python: Print 3 consecutives lines from a PIPE

i have the following code:

def cmds(cmd):
    cmd= Popen(cmd, shell=True, stdout=PIPE)
    lines = command.stdout.read().splitlines()

I have a command that outputs lines like this:

2011/03/30-201
CLIENT 3
Failed
23:17
0.0000

2011/03/31-3
CLIENT 2
Completed
00:47
1.0019

I want to read the first 3 lines for a block, then more 3 lines for next block and more 3 ... I do have no idea how to do this.

Upvotes: 0

Views: 931

Answers (2)

Kirk Strauser
Kirk Strauser

Reputation: 30957

Untested:

def cmds(cmd):
    infile = Popen(cmd, shell=True, stdout=PIPE).stdout
    print infile.readline()
    print infile.readline()
    print infile.readline()
    while True:
        line = infile.readline()
        if not line:
            break
        if line == '\n':
            print infile.readline()
            print infile.readline()
            print infile.readline()

That has the advantage of working on arbitrarily huge files because it only stores the data it's currently working on and not the entire output of your command.

Upvotes: 3

Blender
Blender

Reputation: 298532

Well, if lines = command.stdout.read().splitlines() produces a list of lines like this:

['2011/03/30-201', 'CLIENT 3', 'Failed', '23:17', '0.0000', '', '2011/03/31-3', 'CLIENT 2', 'Completed', '00:47', '1.0019']

You can just loop through it and print until you encounter a blank entry, then reset the counter. It's not very elegant, but it's the most naïve way of doing it:

lines = command.stdout.read().splitlines()
i = 0

for line in lines:
  if line != '':
    if i < 3:
      print(line)
  else:
    i = 0

  i += 1

Upvotes: 3

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