CODEWITHSUNDEEP
pythondictionary
pyds_learner
pyds_learner

Reputation: 519

Sorting nested dictionary according to a key

i have a dictionary as below :

{' PLATINUM': [{'Name': 'MATH',
   'Description': 'You can earn up to 50 Rs per year',
   'value': 50},
  {'Name': 'SCIENCE',
   'Description': 'You can earn up to 100 Rs per year',
   'value': 100},
  {'Name': 'TOTAL',
   'Description': 'You can earn up to 200 Rs per year',
   'value': 200},
  {'Name': 'SOCIAL',
   'Description': 'You can earn up to 50 Rs per year',
   'value': 50}],
 'TITANIUM': [{'Name': 'SOCIAL',
   'Description': 'You can earn up to 20 Rs per year',
   'value': 20},
  {'Name': 'MATH',
   'Description': 'You can earn up to 10 Rs per year',
   'value': 10},
  {'Name': 'TOTAL',
   'Description': 'You can earn up to 30 Rs per year',
   'value': 30}]}

I wanted it to be sorted at each level - 'PLATINUM','TITANIUM' (as many levels) with the 'value'. so expected dictionary will look like :

{' PLATINUM': [
  {'Name': 'TOTAL',
   'Description': 'You can earn up to 200 Rs per year',
   'value': 200},
  {'Name': 'SCIENCE',
   'Description': 'You can earn up to 100 Rs per year',
   'value': 100},
  {'Name': 'MATH',
   'Description': 'You can earn up to 50 Rs per year',
   'value': 50},
  {'Name': 'SOCIAL',
   'Description': 'You can earn up to 50 Rs per year',
   'value': 50}],
 'TITANIUM': [ 
  {'Name': 'TOTAL',
   'Description': 'You can earn up to 30 Rs per year',
   'value': 30}
  {'Name': 'SOCIAL',
   'Description': 'You can earn up to 20 Rs per year',
   'value': 20},
  {'Name': 'MATH',
   'Description': 'You can earn up to 10 Rs per year',
   'value': 10}]}

Can any one help me to achieve it with python code ?

Upvotes: 0

Views: 48

Answers (1)

yatu
yatu

Reputation: 88305

You could use the following dictionary comprehension, where the inner dictionaries are sorted according to the key value:

from operator import itemgetter 
d = {' PLATINUM': [{'Name': 'MATH', 'Description': 'You ...'}

{k:sorted(d[k], key=itemgetter('value'), reverse=True) for k in d}

Output 

{' PLATINUM': [{'Name': 'TOTAL',
   'Description': 'You can earn up to 200 Rs per year',
   'value': 200},
  {'Name': 'SCIENCE',
   'Description': 'You can earn up to 100 Rs per year',
   'value': 100},
  {'Name': 'MATH',
   'Description': 'You can earn up to 50 Rs per year',
   'value': 50},
  {'Name': 'SOCIAL',
   'Description': 'You can earn up to 50 Rs per year',
   'value': 50}],
 'TITANIUM': [{'Name': 'TOTAL',
   'Description': 'You can earn up to 30 Rs per year',
   'value': 30},
  {'Name': 'SOCIAL',
   'Description': 'You can earn up to 20 Rs per year',
   'value': 20},
  {'Name': 'MATH',
   'Description': 'You can earn up to 10 Rs per year',
   'value': 10}]}

Upvotes: 1

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