CODEWITHSUNDEEP
javascriptarrays
Greenbird
Greenbird

Reputation: 35

Javascript remove connected items in array

I have some js arrays. For example:

var array1 ="Apple","Orange","Lemon";
var array2 ="Shop1","Shop2","Shop3";
var array3 ="1","NA","4";
var finalArray=[];
finalArray.push(array1,array2,array3);

The items in each array are linked as I am using them to generate a chart. However, how can remove linked items from finalArray so that if array3 contains 'NA' then each linked item is removed from finalArray. Thus finalArray would contain:

array1 ="Apple","Orange";
array2 ="Shop1","Shop3";
array3 ="1","4";

Any help or pointers in the right direction is appreciated.

Upvotes: 0

Views: 55

Answers (2)

Nina Scholz
Nina Scholz

Reputation: 386736

You could iterate the array with the flags from the end and splice all arrays of finalArray.

var array1 = ["Apple", "Orange", "Lemon"],
    array2 = ["Shop1", "Shop2", "Shop3"],
    array3 = ["1", "NA", "4"],
    finalArray = [array1, array2, array3],
    i = array3.length;

while (i--) {
    if (array3[i] !== 'NA') continue;
    finalArray.forEach(a => a.splice(i, 1));
}

console.log(finalArray);   
.as-console-wrapper { max-height: 100% !important; top: 0; }

Upvotes: 0

Code Maniac
Code Maniac

Reputation: 37755

You can use reduce

Here idea is

  • Loop through the array3 and check whether the value of particular element is NA or not.
  • If it's not NA push the values to respective keys.
  • If it's NA just simply return op without any change.

var array1 =["Apple","Orange","Lemon"];
var array2 =["Shop1","Shop2","Shop3"];
var array3 =["1","NA","4"];

var finalArray = array3.reduce((op,inp,index) => {
  if( inp != 'NA') {
    op.array1.push(array1[index])
    op.array2.push(array2[index])
    op.array3.push(inp)
  }
  return op
},{array1:[], array2:[], array3:[]})

console.log(finalArray)

Upvotes: 1

Related Questions