CODEWITHSUNDEEP
pythonpython-3.xstringreplaceformatting
Rahul Sharma
Rahul Sharma

Reputation: 2495

Replace and remove items from a string

I want to replace my_string

my_string = '[[4.6, 4.3, 4.3, 85.05], [8.75, 5.6, 6.6, 441.0], [4.6, 4.3, 4.3, 85.9625]]'

such that it gives result like this

my_string = '4.6x4.3x4.3 8.75x5.6x6.6 4.6x4.3x4.3'

last_item = '85.05 441.0 85.9625'

The last items in the list has no fixed length For the first objective I've written 

mystring = mystring.replace("[","").replace("]","").replace(", ","x")

But I need a more pythonic way.

Upvotes: 1

Views: 96

Answers (3)

nmb.ten
nmb.ten

Reputation: 2228

Your string looks like valid json string. Maybe like this:

import json
def to_str(lst):
    return 'x'.join([str(e) for e in lst])
my_string = '[[4.6, 4.3, 4.3, 85.05], [8.75, 5.6, 6.6, 441.0], [4.6, 4.3, 4.3, 85.9625]]'
temp = json.loads(my_string)
first_items = ' '.join([to_str(x[:-1]) for x in temp])
last_items = ' '.join([str(x[-1]) for x in temp])
print(first_items)
print(last_items)

Upvotes: 0

Arkistarvh Kltzuonstev
Arkistarvh Kltzuonstev

Reputation: 6935

Try this if my_string = '[[4.6, 4.3, 4.3, 85.05], [8.75, 5.6, 6.6, 441.0], [4.6, 4.3, 4.3, 85.9625]]':

import ast
my_string = " ".join(["x".join([str(k) for k in i[:-1]]) for i in ast.literal_eval(my_string)])
last_item = " ".join([str(k[-1]) for k in ast.literal_eval(my_string)])

UPDATE :

In your question, my_string = '[[4.6, 4.3, 4.3, 85.05], [8.75, 5.6, 6.6, 441.0] [4.6, 4.3, 4.3, 85.9625]]'. If you intend to use this as my_string, then try this :

my_string = " ".join(["x".join([str(k) for k in i[:-1]]) for i in [i.replace(",","").split() for i in my_string.replace("[","").split("]") if len(i) >1]])
last_item = " ".join([str(k[-1]) for k in [i.replace(",","").split() for i in my_string.replace("[","").split("]") if len(i) >1

In the second case, we first do my_string.replace("[","") which results in '4.6, 4.3, 4.3, 85.05], 8.75, 5.6, 6.6, 441.0] 4.6, 4.3, 4.3, 85.9625]]'. Now we split them with .split("]") which results into ['4.6, 4.3, 4.3, 85.05', ', 8.75, 5.6, 6.6, 441.0', ' 4.6, 4.3, 4.3, 85.9625', '', '']. We need to remove the items here which are just vacant string, so we incorporate if len(i) >1 part in the list comprehension. Now we get ['4.6, 4.3, 4.3, 85.05', ', 8.75, 5.6, 6.6, 441.0', ' 4.6, 4.3, 4.3, 85.9625']. We need to remove the commas in the string items of the list. So for each item in this list we do .replace(",","") and then followed by .split() which now results in [['4.6', '4.3', '4.3', '85.05'], ['8.75', '5.6', '6.6', '441.0'], ['4.6', '4.3', '4.3', '85.9625']]. Now for each sublist, we take items upto the last one and we do "x".join() and assign to my_string. Taking that list we can add all the last items with " ".join() and assign that to last_item variable.

Upvotes: 4

Navin Gelot
Navin Gelot

Reputation: 1334

Try using dict

my_string = '[[4.6, 4.3, 4.3, 85.05], [8.75, 5.6, 6.6, 441.0], [4.6, 4.3, 4.3,` 85.9625]]'

    b = {'[': '', ']': '', ',': 'x'}
    for x, y in b.items():
        my_string = my_string.replace(x, y)
    print(my_string)

Upvotes: 0

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