CODEWITHSUNDEEP
pythonpandasdataframe
user2958481
user2958481

Reputation: 607

concatenate pandas rows if next row has NaN in specific column

I have csv file parsed from pdf file and it is not correctly parsed as the table in pdf file has multiple rows. importing it into pd DataFrame looks like this. 

        Record                            Operational Address       BIC
2   2007-03-03  Omladinskih Brigada 90V 11070 BEOGRAD SERBIA,  AAAARSBG
3          NaN                                    REPUBLIC OF       NaN
4   1994-03-07           SAFAT ALI AL SALEM STREET, MUBARAKIA  AAACKWKW
5          NaN           OPPOSITE PUBLIC LIBRARY 13022 KUWAIT       NaN
6          NaN                                         KUWAIT       NaN
7   2006-06-03           CHEZ NSM 3, AVENUE HOCHE 75008 PARIS  AAADFRP1
8          NaN                                         FRANCE       NaN
9   2006-06-03           10 RUE DU COLISEE 75008 PARIS FRANCE  AAAGFRP1
10         NaN                                            NaN       NaN
11  2014-07-05           152, 6TH OF SEPTEMBER BLVD. BUSINESS  AAAJBG21
12         NaN             CENTER LEGIS 4000 PLOVDIV BULGARIA       NaN
13  1989-03-29       DHABAB STREET HEAD OFFICE BUILDING 11431  AAALSARI
14         NaN                            RIYADH SAUDI ARABIA       NaN

I want to concatenate next rows into current row if next value in Record column is NaN.

I mean I want to get 

        Record                                                                       Operational Address        BIC
2   2007-03-03  Omladinskih Brigada 90V 11070 BEOGRAD SERBIA, REPUBLIC OF                                  AAAARSBG
4   1994-03-07           SAFAT ALI AL SALEM STREET, MUBARAKIA OPPOSITE PUBLIC LIBRARY 13022 KUWAIT KUWAIT  AAACKWKW
7   2006-06-03           CHEZ NSM 3, AVENUE HOCHE 75008 PARIS FRANCE                                       AAADFRP1
9   2006-06-03           10 RUE DU COLISEE 75008 PARIS FRANCE                                              AAAGFRP1
11  2014-07-05           152, 6TH OF SEPTEMBER BLVD. BUSINESS CENTER LEGIS 4000 PLOVDIV BULGARIA           AAAJBG21
13  1989-03-29       DHABAB STREET HEAD OFFICE BUILDING 11431 RIYADH SAUDI ARABIA                          AAALSARI

here is dataframe

import numpy a np
data = {'Record': {2: '2007-03-03',
                   3: np.NaN,
                   4: '1994-03-07',
                   5: np.NaN,
                   6: np.NaN,
                   7: '2006-06-03',
                   8: np.NaN,
                   9: '2006-06-03',
                   10: np.NaN,
                   11: '2014-07-05',
                   12: np.NaN,
                   13: '1989-03-29',
                   14: np.NaN},
        'Operational Address': {2: 'Omladinskih Brigada 90V 11070 BEOGRAD SERBIA,',
                                3: 'REPUBLIC OF',
                                4: 'SAFAT ALI AL SALEM STREET, MUBARAKIA',
                                5: 'OPPOSITE PUBLIC LIBRARY 13022 KUWAIT',
                                6: 'KUWAIT',
                                7: 'CHEZ NSM 3, AVENUE HOCHE 75008 PARIS',
                                8: 'FRANCE',
                                9: '10 RUE DU COLISEE 75008 PARIS FRANCE',
                                10: np.NaN,
                                11: '152, 6TH OF SEPTEMBER BLVD. BUSINESS',
                                12: 'CENTER LEGIS 4000 PLOVDIV BULGARIA',
                                13: 'DHABAB STREET HEAD OFFICE BUILDING 11431',
                                14: 'RIYADH SAUDI ARABIA'},
        'BIC': {2: 'AAAARSBG',
                3: np.NaN,
                4: 'AAACKWKW',
                5: np.NaN,
                6: np.NaN,
                7: 'AAADFRP1',
                8: np.NaN,
                9: 'AAAGFRP1',
                10: np.NaN,
                11: 'AAAJBG21',
                12: np.NaN,
                13: 'AAALSARI',
                14: np.NaN}}

df = pd.DataFrame(data=data)

Upvotes: 3

Views: 1071

Answers (1)

ALollz
ALollz

Reputation: 59579

Use cumsum to form groups and specify a dictionary for aggregation for each column.

agg_d = {'Record': 'first', 
         'Operational Address': lambda x: ' '.join(x.dropna()),
         'BIC': 'first'}

df.groupby(df.Record.notnull().cumsum().rename(None)).agg(agg_d)

       Record                                                               Operational Address       BIC
1  2007-03-03  Omladinskih Brigada 90V 11070 BEOGRAD SERBIA, REPUBLIC OF                         AAAARSBG
2  1994-03-07  SAFAT ALI AL SALEM STREET, MUBARAKIA OPPOSITE PUBLIC LIBRARY 13022 KUWAIT KUWAIT  AAACKWKW
3  2006-06-03  CHEZ NSM 3, AVENUE HOCHE 75008 PARIS FRANCE                                       AAADFRP1
4  2006-06-03  10 RUE DU COLISEE 75008 PARIS FRANCE                                              AAAGFRP1
5  2014-07-05  152, 6TH OF SEPTEMBER BLVD. BUSINESS CENTER LEGIS 4000 PLOVDIV BULGARIA           AAAJBG21
6  1989-03-29  DHABAB STREET HEAD OFFICE BUILDING 11431 RIYADH SAUDI ARABIA                      AAALSARI

Upvotes: 2

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