CODEWITHSUNDEEP
javaandroid
abefroman
abefroman

Reputation: 149

try catch block still returning exception that is supposed to catch

I'm pretty new to android development and i'm working my way through some sample programs. currently i'm attempting to use a try catch block to prevent the application to crash if the user just presses the created button without entering a number and selecting a route. The try-catch unfortunately is not working as the app keeps crashing and returning the same NumberFormatException. This is a sample of what my code looks like so far. 

handleSubmit.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        handleInput = findViewById(R.id.groupInput);
        int numAthletes = Integer.parseInt(handleInput.getText().toString());
        int totalCost;

        try {
            if(dropDown.getSelectedItem().toString().equals("Route 1") ||
                    dropDown.getSelectedItem().toString().equals("Route 2") ||
                    dropDown.getSelectedItem().toString().equals("Route 3") ){
                totalCost = numAthletes * 725;
                displayData.setText(dropDown.getSelectedItem().toString() + " Race Team Fee is  - $" + Integer.toString(totalCost));
            }
        }catch (NumberFormatException e){
            Log.e( "onClick: ","Empty submission" );

        }

    }
});

this is the error that is not being catched.

java.lang.NumberFormatException: For input string: ""

Upvotes: 0

Views: 49

Answers (1)

Jackey
Jackey

Reputation: 3234

You're not catching the right line. 

int numAthletes = Integer.parseInt(handleInput.getText().toString());

That's the line causing the exception, but you've placed it outside of the try{} block.

Upvotes: 3

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