CODEWITHSUNDEEP
linuxshellcommand-linedebian
SamuelPherson
SamuelPherson

Reputation: 21

How invoke dpkg-buildflags for manual compilation?

On Debian stretch when trying to manually compile e.g. libpopt (I'm not intending to create debian packages), after I did export DEB_BUILD_OPTIONS=hardening=+all I've trouble passing dpkg-buildflags to ./configure:

./configure $(dpkg-buildflags --export=cmdline)
configure: error: unrecognized option: -O2
Try `./configure --help' for more information.

If I do:

dpkg-buildflags --export=cmdline

I get:

CFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong -Wformat -Werror=format-security" CPPFLAGS="-Wdate-time -D_FORTIFY_SOURCE=2" CXXFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong -Wformat -Werror=format-security" FCFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong" FFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong" GCJFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong" LDFLAGS="-Wl,-Bsymbolic-functions -Wl,-z,relro -Wl,-z,now" OBJCFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong -Wformat -Werror=format-security" OBJCXXFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong -Wformat -Werror=format-security"

When I now pass this output manually (copy&paste) to ./configure it works:

./configure CFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong -Wformat -Werror=format-security" CPPFLAGS="-Wdate-time -D_FORTIFY_SOURCE=2" CXXFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong -Wformat -Werror=format-security" FCFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong" FFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong" GCJFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong" LDFLAGS="-Wl,-Bsymbolic-functions -Wl,-z,relro -Wl,-z,now" OBJCFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong -Wformat -Werror=format-security" OBJCXXFLAGS="-g -O2 -fdebug-prefix-map=/home/user/popt-1.16=. -fstack-protector-strong -Wformat -Werror=format-security"
checking build system type... x86_64-unknown-linux-gnu
[...]

How can I invoke dpkg-buildflags to automatically pass its flags to ./configure? Why does manual copy&paste work but not the other approach?

Upvotes: 2

Views: 193

Answers (1)

fixeria
fixeria

Reputation: 126

Why does manual copy&paste work but not the other approach?

This is related to argument escaping. Consider the following function:

# This function simply prints its arguments, each on separate line
test () {
    for arg in "$@"; do
        echo "$arg"
    done
}

This is what happens when you pass the output of dpkg-buildflags manually:

$ test ROSES=red VIOLETS=blue CFLAGS="-O0 -ggdb"
ROSES=red
VIOLETS=blue
CFLAGS=-O0 -ggdb

Note that CFLAGS=-O0 -ggdb is seen as a single argument, so escaping works.

Now let's try to evaluate an inline expression:

$ test $(echo ROSES=red VIOLETS=blue CFLAGS="-O0 -ggdb")
ROSES=red
VIOLETS=blue
CFLAGS=-O0
-ggdb

Boom! Somehow CFLAGS=-O0 -ggdb got broken into CFLAGS=-O0 and -ggdb. The same is happening in your case: the value of CFLAGS gets split into multiple arguments, and indeed -O2 is not a valid option. This is why you're getting an error.

How can I invoke dpkg-buildflags to automatically pass its flags to ./configure?

You can work this around using a pipe and xargs command:

dpkg-buildflags --export=cmdline | xargs ./configure

This solution works for me.

Upvotes: 1

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