CODEWITHSUNDEEP
pythonpython-3.xnested-lists
José Vallejo
José Vallejo

Reputation: 356

Create tuples from a list in Python

I have this array:

lst = ['A', 'B', 'C']

How could I append a string 'D' to each element and convert every set as a tuple:

lst2=  [('A', 'D'),
          ('B', 'D'),
          ('C', 'D')]

Upvotes: 0

Views: 4347

Answers (6)

Mykola Zotko
Mykola Zotko

Reputation: 17834

You can use the function product():

from itertools import product

lst = ['A', 'B', 'C']

list(product(lst, 'D'))
# [('A', 'D'), ('B', 'D'), ('C', 'D')]

Upvotes: 1

Wanmi Siangshai
Wanmi Siangshai

Reputation: 142

list1 = ['A', 'B', 'C']
list2 = []
for i in list1:
    list2.append((i, 'D'))
print(list2)

Upvotes: 1

user8060120
user8060120

Reputation:

alternative solution is use zip_longest

from itertools import zip_longest
list(zip_longest(['A', 'B', 'C'], [], fillvalue='D'))

the result wiil be:

[('A', 'D'), ('B', 'D'), ('C', 'D')]

Upvotes: 3

obchardon
obchardon

Reputation: 10792

Another option using zip:

x = ['A', 'B', 'C']
res = list(zip(x,'D'*len(x)))

Upvotes: 1

Óscar López
Óscar López

Reputation: 236034

Like this, using a list comprehension:

lst  = ['A', 'B', 'C']
lst2 = [(x, 'D') for x in lst]

lst2
=> [('A', 'D'), ('B', 'D'), ('C', 'D')]

By the way, it's a bad idea to call a variable list, that clashes with a built-in function. I renamed it.

Upvotes: 5

glglgl
glglgl

Reputation: 91059

list2 = [(i, 'D') for i in list]

(apart from the fact that list is a very bad variable name)

Upvotes: 1

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