CODEWITHSUNDEEP
swiftcodableencodable
user11198154
user11198154

Reputation:

Errors when using Codable - Swift

I am using Codable to try to Encode JSON to a Model but I get two errors. Value of type 'KeyedEncodingContainer' has no member 'encoder'

Here's my code:

import UIKit

struct NewCustomer : Codable {

    var firstName :String
    var lastName :String


    private enum CodingKeys : String, CodingKey {
        case firstName
        case lastName
    }

    func encode(to encoder :Encoder) throws {

        var container = encoder.container(keyedBy: CodingKeys.self)
        try container.encoder(self.firstName, forKey: .firstName)  // error here
        try container.encoder(self.lastName, forKey: .lastName)  // error here
    }
}

let customer = NewCustomer(firstName: "Jake", lastName: "Reynolds")

let encodedCustomerJSON = try! 
JSONEncoder().encode(customer)

print(encodedCustomerJSON)

print(String(data: encodedCustomerJSON, encoding: .utf8)!)

Upvotes: 1

Views: 77

Answers (2)

vadian
vadian

Reputation: 285064

As already mentioned it's a typo encode vs. encoder:

try container.encode(...

Practically you don't need to specify CodingKeys and the encoding method at all in this case, this is sufficient:

struct NewCustomer : Codable {
    var firstName, lastName : String
}

Upvotes: 0

user11104208
user11104208

Reputation:

Change encoder to encode on the two lines giving errors. Please note that the line above (i.e. var container...) will keep encoder.

try container.encode(self.firstName, forKey: .firstName)
try container.encode(self.lastName, forKey: .lastName)

Upvotes: 2

Related Questions