CODEWITHSUNDEEP
perl
chotchki
chotchki

Reputation: 4343

How to convert an array reference to an array in Perl?

I know I can create an array and a reference to an array as follows:

my @arr = ();
my $rarr = \@arr;

I can then iterate over the array reference as follows:

foreach my $i (@{$rarr}){

}

Is there a way to copy or convert the array ref to a normal array so I can return it from a function? (Ideally without using that foreach loop and a push).

Upvotes: 21

Views: 30527

Answers (3)

Mat
Mat

Reputation: 206919

You have the answer in your question :-)

use warnings;
use strict;

sub foo() {
    my @arr = ();
    push @arr, "hello", ", ", "world", "\n";
    my $arf = \@arr;
    return @{$arf}; # <- here
}

my @bar = foo();
map { print; } (@bar);

Upvotes: 22

Paul Beckingham
Paul Beckingham

Reputation: 14925

Like this:

return @{$reference};

You're then just returning a dereferenced reference.

Upvotes: 11

ennuikiller
ennuikiller

Reputation: 46985

you can copy the array simply by assigning to a new array:

my @copy_of_array = @$array_ref;

BUT, you don't need to do that just to return the modified array. Since it's a reference to the array, updating the array through the reference is all you need to do!

Upvotes: 4

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