CODEWITHSUNDEEP
phpcodeigniterternary-operator
Jacky
Jacky

Reputation: 781

How to write more than one condition in ternary operator in codeigniter?

My Picture:

enter image description here

In this picture i am saving group type using radio button.if balance sheet is selected it saved as "B" and profit and loss as "P".if without select anything,it save as "T".

Now my problem is i am using ternary operator to check conditions,but for me only 2nd conditions is working.It is not working for more than one conditions in that operator. How i resolve my problem.

public function GEntry()
{

        $session_data = $this->session->userdata('logged_in');
        $data['username'] = $session_data['username'];
        $this->form_validation->set_rules('gName', 'gName', 'required');

        $this->form_validation->set_error_delimiters('<div class="text-danger">',
            '</div>');
        $check1 = isset($_POST['gType']);

        $check =  ($check1 == 'B') ? "B"  : ($check1 == 'P') ? "P" :'T';
    //$check1 = isset($_POST['tin_no1']) ? "Y" : "N";

        if ($this->form_validation->run())
        {
            $data= array(
                'gName' => $this->input->post('gName'),
                'gType' => $check
                );
        //means insert a data into the table
            $this->db->insert('groups',$data);

            return redirect('Master/Groups');
        }

Upvotes: 1

Views: 2657

Answers (2)

CodiMech25
CodiMech25

Reputation: 446

You can capture an entire ternary operator with using brackets like this:

$a = ($b === 'A') ? 'A' : (($b === 'B') ? 'B' : (($b === 'C') ? 'C' : 'D'));

BUT ... i would not recommend you this procedure, if your decisioning takes more than 2-3 conditions. In that case, i would recommend you, to use a switch instead:

switch ($b)
{
    case 'A':
        $a = 'A';
        break;
    default:
        $a = 'D';
        break;
}

ALSO ... i would recommend you to use a === comparator instead of the == comparator like in the code provided by you. The third = makes sure, that both of the given values are of the same data type, so you compare a string with another string in your example.

Upvotes: 0

Saji
Saji

Reputation: 1394

You are not assigning the post data to the variable $check1. You are checking like this $check1 = isset($_POST['gType']); this will give you true / false.

Update like below:

$check1 = isset($_POST['gType']) && in_array($_POST['gType'], ['B', 'P']) ? $_POST['gType'] : 'T';

Then remove this line $check = ($check1 == 'B') ? "B" : ($check1 == 'P') ? "P" :'T';

Upvotes: 1

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