Reputation: 311
I need to concatenate two strings that are in different lists and check if the output string is in a dictionary. The code I've tried is:
x=['casa','lo','pre','computer']
y=['music','sun','ve','sident','house']
dic=['sunday','love','president','house','computer']
text=[]
errors=[]
iter_y=iter(y)
iter_x=iter(x)
for i in iter_x:
if i in dic:
text.append(i)
else:
try:
concatenated= i + next(iter_y)
if concatenated in dic:
text.append(concatenated)
except StopIteration:
continue
else:
errors.append(i)
print (text)
This code is returning only the word that is common to x and y ('Computer'). My desired output is x=[love, president, computer] That is, with the words love and president concatenated in the output.
Upvotes: 1
Views: 379
Reputation: 185
Here's a straightforward version with nothing fancy. Others have suggested options that are likely more efficient; however, I think this solution captures your desired solution better than some (e.g., by checking all variations of concatenations).
You will want to use sets if you're doing a lot of lookups.
x = ['casa','lo','pre','computer']
y = ['music','sun','ve','sident','house']
dic = set(['sunday','love','president','house','computer'])
in_dic = set()
for str in y:
if str in dic:
in_dic.add(str)
for str1 in x:
if str1 in dic:
in_dic.add(str1)
for str2 in y:
str3 = str1 + str2
str4 = str2 + str1
if str3 in dic:
in_dic.add(str3)
if str4 in dic:
in_dic.add(str4)
print(list(in_dic))
['president', 'love', 'computer', 'house']
Upvotes: 0
Reputation: 8273
IIUC then you can use itertools.product
to get product of two different lists and then perform set intersection to find the common words
from itertools import product
x=['casa','lo','pre','computer']
y=['music','sun','ve','sident','house']
dic=['sunday','love','president','house','computer']
set(list(map(''.join, list(product(x, y)))) + x + y) & set(dic)
OUTPUT:
{'computer', 'house', 'love', 'president'}
If the expected output should not include house
from second list then do not append list y
in the final concatenated list
set(list(map(''.join, list(product(x, y)))) + x) & set(dic)
OUTPUT
{'computer', 'love', 'president'}
Upvotes: 2
Reputation: 635
Does this work for you?
x=['casa','lo','pre','computer']
y=['music','sun','ve','sident','house']
dic=['sunday','love','president','house','computer']
possibles = []
possibles += x
possibles += y # if you want the house...
hits = []
for a in x:
for b in y:
possibles.append(a+b)
for a in y:
for b in x:
possibles.append(a+b)
for p in possibles:
if p in dic:
hits.append(p)
print(p)
Upvotes: 0
Reputation: 4343
For a one liner use filter
, ''.join
and add ['']
to the second list (so you don't have to do two if
s):
list(filter(lambda i: i in dic, [''.join((s1, s2)) for s1 in x for s2 in (y + [''])]))
>>['love', 'president', 'computer']
Upvotes: 0
Reputation: 19242
With your approach, you need to reset the iterator over y
each time you try a new value in x
.
It might be clearer like this:
for i in x:
if i in dic:
text.append(i)
else:
for j in y:
concatenated = i + j
if concatenated in dic:
text.append(concatenated)
The for j in y
tries all the things in y
, otherwise it moves on each time, and never looks back.
Upvotes: 0