CODEWITHSUNDEEP
c++
Sirius 26
Sirius 26

Reputation: 43

C++ How to print Big letters Horizontally?

for example, a have this function that prints a big "A"

void printA(){
    cout<<"0000000\n0     0\n0     0\n0000000\n0     0\n0     0\n";
}

0000000
0     0
0     0
0000000
0     0
0     0

I have all the alphabet, is there a way I can print the big letters horizontally? like:

0000000  0000000  0000000
0     0  0     0  0     0
0     0  0     0  0     0
0000000  0000000  0000000
0     0  0     0  0     0
0     0  0     0  0     0

the goal of the program is to print the user's input with these big letters, vertically or horizontally.

here is a resumed version of my program:

void printA(){
    cout<<"0000000\n0     0\n0     0\n0000000\n0     0\n0     0\n"<<endl;
}

void printChar(char c){
    c = toupper(c);
    if (c=='A')
    printA();

}
int main(){

string sentence;
cout<<"enter sentence: ";
cin>> sentence;

for(unsigned int i = 0; i<sentence.length(); i++) {
    char c = sentence[i];
    if(c=='a')
    printA();
}
return 0;

}

I made the letter functions with the "\n" to save lines, another option is to make them like this:

void printA(){
    cout << "0000000" << endl;
    cout << "0     0" << endl;
    cout << "0     0" << endl;
    cout << "0000000" << endl;
    cout << "0     0" << endl;
    cout << "0     0" << endl;
}

if is not possible to print them next to each other in the way i have them, i will rewrite them, but please tell me how to print them in horizontal form :( thank you!

I have the following alerts:

main.cpp:29:23: warning: range-based 'for' loops only available with -std=c++11 or -std=gnu++11
         for (char c : text)
                       ^
main.cpp:31:37: warning: 'c' may be used uninitialized in this function [-Wmaybe-uninitialized]
             std::cout << alphabet[c - 'A'][line] << "  ";

Upvotes: 1

Views: 4909

Answers (1)

Nico Schertler
Nico Schertler

Reputation: 32627

If you can store the lines of your characters in a different format (here, a 2D array) like so:

const int LINES_PER_CHAR = 6;
const char* alphabet[][LINES_PER_CHAR] = 
{
    /* A */ { "0000000", "0     0", "0     0", "0000000", "0     0", "0     0" },
    /* B */ { "000 ", "0  0", "0  0", "000 ", "0  0", "0000" }
    ...
};

…, then you can print the characters like this:

void PrintBigString(const std::string& text)
{
    for (int line = 0; line < LINES_PER_CHAR; ++line)
    {
        for (char c : text)
        {
            std::cout << alphabet[c - 'A'][line] << "  ";
        }
        std::cout << std::endl;
    }
}

Ideally, you should add a sanity check that makes sure that you have the template for the current character in the string.

Variation for non-C++11 compilers:

void PrintBigString(const std::string& text)
{
    for (int line = 0; line < LINES_PER_CHAR; ++line)
    {
        for (int i = 0; i < text.size(); ++i)
        {
            std::cout << alphabet[text[i] - 'A'][line] << "  ";
        }
        std::cout << std::endl;
    }
}

Upvotes: 4

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