CODEWITHSUNDEEP
phparraysjsonsymfonysymfony4
Khalil
Khalil

Reputation: 388

How to return json without its key

I have Route /json.json return 

[{"titre":"Symfony"},{"titre":"Laravel"},{"titre":"test"}]

But I want to return only values like : 

["Symfony","Laravel","test"]

This is my controller

   /**
     * @Route("/tags.json", name="liste_tags")
     * @param Request $request
     * @return \Symfony\Component\HttpFoundation\JsonResponse
     */
    public function index()
    {

        $tags = $this->getDoctrine()
            ->getRepository(Tag::class)
            ->findAll();
        return $this->json($tags, 200, [], ['groups' => ['public'] ]);
    }

With this annotation in entity

/**
 * @param string $titre
 * @Groups({"public"})
 * @return Tag
 */
public function setTitre(string $titre): self
{
    $this->titre = $titre;

    return $this;
}

Upvotes: 0

Views: 560

Answers (2)

Paweł Napierała
Paweł Napierała

Reputation: 1755

You can use the function array_column to get the values from the titre column

$tags = array_column($tags, 'titre');

Upvotes: 4

Anthony
Anthony

Reputation: 2132

If you are sure the keys will always be titre, you can use array_map

<?php
//Your JSON, decoded to get an array
$array = json_decode('[{"titre":"Symfony"},{"titre":"Laravel"},{"titre":"test"}]', true);

// Loop over the array to fetch only the value of "titre".
$result = array_map(function($e) {
    return $e['titre'];
}, $array);

var_dump($result);

It should show:

array(3) {
  [0] =>
  string(7) "Symfony"
  [1] =>
  string(7) "Laravel"
  [2] =>
  string(4) "test"
}

Upvotes: 0

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