Reputation: 503
I have these two tables and I need to find the department name with maximum number of employees.
The other solutions were not for Oracle, so I'm posting this question. Also, it would be really helpful if the query can be explained thoroughly as I'm finding it hard to visualise it.
EMPLOYEE
EMPNO EMPNAME MANAGER SALARY DEPT_NO
1 Puja 6 30000 2
2 Purabi 1 15000 3
3 Barun 6 23000 2
4 Sudha 1 20000 1
5 Amal 2 20000 1
6 Rakesh 3 30000 4
DEPARTMENT
Dept_No Dept_Name Location
1 Production LaneA
2 Marketing LaneB
3 Sales LaneC
4 HR LaneD
So far I could manage getting the highest number of employees. So I was thinking if somehow I can write another sub-query where I count the employees in the departments again and compare them to the max_num_emp that I calculated in the first query.
This is the query which retrieves the maximum number of employees. It does not return the dept_no.
select count(dept_no)
from employee
group by dept_no
order by count(dept_no) desc
fetch first row only;
Expected output
DEPT_NAME
Production
Marketing
I can also add the dept_no column in the query, then I will have to somehow find out how to get the max and that was somehow giving me errors because the query was violating some rules. I had actually tried doing max(above query).
So I thought of just getting the maximum employee count and then determine all departments which have those many employees and display their name.
Upvotes: 1
Views: 4891
Reputation: 31648
You may have used FETCH..FIRST
syntax using WITH TIES
instead of ONLY
.
SELECT d.dept_name
FROM department d
JOIN employee e ON d.dept_no = e.dept_no
GROUP BY d.dept_name
ORDER BY COUNT(*)
DESC FETCH FIRST 1 ROW WITH TIES ;
Upvotes: 2
Reputation: 164089
You have a working query which you need to join to the table department
:
select d.Dept_Name
from department d inner join (
select dept_no
from employee
group by dept_no
order by count(*) desc
fetch first row only
) t
on t.dept_no = d.dept_no
Edit
Try this (I cannot try it):
select d.dept_name
from department d inner join (
select x.dept_no from (
select dept_no, rank() over (order by count(*) desc) rn
from employee
group by dept_no
order by count(dept_no) desc
) x
where x.rn = 1
) t
on t.dept_no = d.dept_no
Upvotes: 3
Reputation: 1269603
If you are not looking for duplicates, then:
select d.dept_name, count(*)
from department d join
employee e
on d.dept_no = e.dept_no
group by d.dept_no, d.dept_name
order by count(dept_no) desc
fetch first row only;
Upvotes: 0