Reputation: 73
Given the code below, how would I go about adding a count column? (e.g. .count("*").as("count"))
Final output to look like something like this:
+---+------+------+-----------------------------+------
| id|sum(d)|max(b)|concat_ws(,, collect_list(s))|count|
+---+------+------+-----------------------------+------
| 1| 1.0| true| a. | 1 |
| 2| 4.0| true| b,b| 2 |
| 3| 3.0| true| c. | 1 |
Current code is below:
val df =Seq(
(1, 1.0, true, "a"),
(2, 2.0, false, "b")
(3, 3.0, false, "b")
(2, 2.0, false, "c")
).toDF("id","d","b","s")
val dataTypes: Map[String, DataType] = df.schema.map(sf => (sf.name,sf.dataType)).toMap
def genericAgg(c:String) = {
dataTypes(c) match {
case DoubleType => sum(col(c))
case StringType => concat_ws(",",collect_list(col(c))) // "append"
case BooleanType => max(col(c))
}
}
val aggExprs: Seq[Column] = df.columns.filterNot(_=="id")
.map(c => genericAgg(c))
df
.groupBy("id")
.agg(aggExprs.head,aggExprs.tail:_*)
.show()
Upvotes: 0
Views: 407
Reputation: 22449
You can simply append count("*").as("count")
to aggExprs.tail
in your agg
, as shown below:
df.
groupBy("id").agg(aggExprs.head, aggExprs.tail :+ count("*").as("count"): _*).
show
// +---+------+------+-----------------------------+-----+
// | id|sum(d)|max(b)|concat_ws(,, collect_list(s))|count|
// +---+------+------+-----------------------------+-----+
// | 1| 1.0| true| a| 1|
// | 3| 3.0| false| b| 1|
// | 2| 4.0| false| b,c| 2|
// +---+------+------+-----------------------------+-----+
Upvotes: 1