Reputation: 192
My objective is : For any given flightDuration, i want to match 2 film from my filmDurations that their sums exactly finishes 30 minutes from flight.
For example :
I can do it with nested loops. But it is not effective and it is time consuming.
I want to do it more effectively. I thinked using Linq but still it is O(n^2).
What is the best effective way?
Edit: I want to clear one thing.
I want to find filmDurations[i] + filmDurations[j] in;
filmDurations[i] + filmDurations[j] == fligtDuration - 30
And say i have very big amont of film durations.
Upvotes: 0
Views: 200
Reputation: 10181
You could sort all durations (remove duplicates) (O(n log n)) and than iterate through them (until the length flight-duration -30). Search for the corresponding length of the second film (O(log n)).
This way you get all duration-pairs in O(n log n).
You can also use a HashMap (duration -> Films) to find matching pairs.
This way you can avoid sorting and binary search. Iterate through all durations and look up in the map if there are entries with duration = (flight-duration -30).
Filling the map needs O(n) lookup O(1) and you need to iterate all durations.
-> Over all complexity O(n) but you loose the possibility to find 'nearly matching pairs which would be easy to implement using the sorted list approach described above)
Upvotes: 2
Reputation: 7054
As Leisen Chang said you can put all items into dictionary. After doing that rewrite your equation
filmDurations[i] + filmDurations[j] == fligtDuration - 30
as
filmDurations[i] == (fligtDuration - 30 - filmDurations[j])
Now for each item in filmDurations
search for (fligtDuration - 30 - filmDurations[j])
in dictionary. And if such item found you have a solution.
Next code implement this concept
public class IndicesSearch
{
private readonly List<int> filmDurations;
private readonly Dictionary<int, int> valuesAndIndices;
public IndicesSearch(List<int> filmDurations)
{
this.filmDurations = filmDurations;
// preprocessing O(n)
valuesAndIndices = filmDurations
.Select((v, i) => new {value = v, index = i})
.ToDictionary(k => k.value, v => v.index);
}
public (int, int) FindIndices(
int flightDuration,
int diff = 30)
{
// search, also O(n)
for (var i = 0; i < filmDurations.Count; ++i)
{
var filmDuration = filmDurations[i];
var toFind = flightDuration - filmDuration - diff;
if (valuesAndIndices.TryGetValue(toFind, out var j))
return (i, j);
}
// no solution found
return (-1, -1); // or throw exception
}
}
Upvotes: 1