CODEWITHSUNDEEP
julia
xiaodai
xiaodai

Reputation: 16014

Is there a lazy and iterative `map` in Julia?

The map function seems eager, e.g.

map(x->x+1, 1:3) gives one [2,3,4].

I want to find a lazy and iterative version of map so that the values are not generated all at once, so I can just get values one by one from the result of the map?

Upvotes: 6

Views: 437

Answers (1)

Bogumił Kamiński
Bogumił Kamiński

Reputation: 69909

You can use Base.Generator for this, e.g. in your case:

julia> g = (x + 1 for x in 1:3)
Base.Generator{UnitRange{Int64},getfield(Main, Symbol("##5#6"))}(getfield(Main, Symbol("##5#6"))(), 1:3)

julia> collect(g)
3-element Array{Int64,1}:
 2
 3
 4

Upvotes: 8

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